Symfony 2 functional test: authenticate user of own User class

Question

As described in answer of How to use an authenticated user in a Symfony2 functional test? there is a simple solution with Symfony\Component\Security\Core\User\User.

But I have different User class (some necessary additional fields) and I want to authenticate user with it.

How can I setup providders for it?

Take a look at this new [cookbook article](http://symfony.com/doc/current/cookbook/testing/simulating_authentication.html) — Emii Khaos, May 14 '13 at 10:12

score 10 · Accepted Answer · answered May 14 '13 at 13:05

This is a tricky issue discussed here: https://github.com/symfony/symfony/issues/5228 Though it is 2.1, it still happen to me using 2.2.

Here is how I do the test authentication:

// Create a new client to browse the application
$client = static::createClient();
$client->getCookieJar()->set(new Cookie(session_name(), true));

// dummy call to bypass the hasPreviousSession check
$crawler = $client->request('GET', '/');

$em = $client->getContainer()->get('doctrine')->getEntityManager();
$user = $em->getRepository('MyOwnBundle:User')->findOneByUsername('username');

$token = new UsernamePasswordToken($user, $user->getPassword(), 'main_firewall', $user->getRoles());
self::$kernel->getContainer()->get('security.context')->setToken($token);

$session = $client->getContainer()->get('session');
$session->set('_security_' . 'main_firewall', serialize($token));
$session->save();

$crawler = $client->request('GET', '/login/required/page/');

$this->assertTrue(200 === $client->getResponse()->getStatusCode());

// perform tests in the /login/required/page here..

Oh, and the use statements:

use Symfony\Component\Security\Core\Authentication\Token\UsernamePasswordToken;
use Symfony\Bundle\FrameworkBundle\Client;
use Symfony\Component\BrowserKit\Cookie;

Actually we use LDAP, not cookies. I found different solution, I'll describe it now in the answer. — Dmitry, May 14 '13 at 19:34
@DmitryR I don't know about LDAP, and you didn't state it in the question. Do you need to make a dummy call just like session based use? — ihsan, May 15 '13 at 01:03
awesome. just remind that in Symfony 3.0.6 the security.context should be security.token_storage ;) — , May 12 '16 at 11:28

score 1 · Answer 2 · answered May 14 '13 at 12:58

are u using a form login ? or http security?

when using the form login what i do in my tests is i just simulate a user logging in via the login form ...

    /**
     * test of superuser ingelogd geraakt
     */
    public function testSuperAdminLogin()
    {
        $crawler = $this->client->request('GET', '/login');
        $form = $crawler->selectButton('Sign In')->form();
        $user = $this->em->getRepository('NonoAcademyBundle:User')
            ->findOneByUsername('superadmin');
        $crawler = $this->client
            ->submit($form,
                array('_username' => $user->getUsername(),
                        '_password' => $user->getPassword()));

        $this->assertTrue($this->client->getResponse()->isSuccessful());

        $this
            ->assertRegExp('/\/admin\/notifications/',
                $this->client->getResponse()->getContent());
    }

then just use that client and crawler, as they will act as the logged in user. Hope this helps you

in this particular case we did, since this particular client actually wanted to be able to re-send existing password, via the pass-forgotten process, instead of starting a resetting procedure, where he is forced to create a new one (we advised him not go go this route, and explained why), but thats what they wanted ... — Sam Janssens, Dec 30 '15 at 11:28

Olotin Temitope · Answer 3 · 2016-09-06T15:51:35.230

You might also find these helpful especially if you are using a form login

private function doLogin()
{
    $this->client = static::createClient();
    $username = 'your-username';
    $password = 'your-password';

    $crawler = $this->client->request('GET', '/login');
    $form = $crawler->filter('your-submit-button-classname')->form();

    $crawler = $this->client
        ->submit($form,
            array(
                '_username' => $username,
                '_password' => $password,
            )
       );
}

score 0 · Answer 4 · answered May 14 '13 at 19:41

0

I found a solution.

First we have to create new user provider: FakeUserProvider as described here.
It should implement UserProviderInterface.

Its loadUserByUsername should create necessary user object.

answered May 14 '13 at 19:41

Dmitry

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Symfony 2 functional test: authenticate user of own User class

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