How do I remove # sign from hash data? jquery?

Question

I need value of hash from url...

var hash = window.location.hash;

So how do I get rid of # sign?

possible duplicate of [What is the difference between slice() and substr() in JavaScript?](http://stackoverflow.com/questions/4546284/what-is-the-difference-between-slice-and-substr-in-javascript) — Danubian Sailor, May 14 '13 at 09:48
@alex23 relax. I still cannot approve answer, 1 min remaining. — , May 14 '13 at 09:55

MildlySerious · Accepted Answer · 2013-05-14T09:50:13.727

As easy as that.

var hash = window.location.hash.substr(1)

There are also these two which return the exact same:

var hash = window.location.hash.slice(1)
var hash = window.location.hash.substring(1)

String.slice() was added to the spec a little later, although that's propably unimportant.

Using replace as mentioned below is an option, too.

None of those options throw an error or warning if the window.location.hash string is empty, so it really depends on your preferences what to use.

Adil Shaikh · Answer 2 · 2017-04-13T06:03:44.723

6

You can do this -

hash = hash.replace(/^#/, '');

edited Apr 13 '17 at 06:03

answered May 14 '13 at 09:43

Adil Shaikh

I think `hash.replace('#','')` is more safe than `slice(1)` – rab May 14 '13 at 09:51
In that case you probably want to use `hash.replace(/^#/, '')` so you exclusively remove a leading `#`, not ones that are part of the hash. – MildlySerious Apr 09 '17 at 19:17

score 1 · Answer 3 · answered May 14 '13 at 09:42

1

Just cut out the first char:

 var hash = window.location.hash.slice(1);

answered May 14 '13 at 09:42

flavian

score 0 · Answer 4 · answered May 14 '13 at 09:42

0

You can simply do

 var hash = window.location.hash.slice(1);

Note that it doesn't produce an error if there is no hash in the location, it just returns "".

answered May 14 '13 at 09:42

Denys Séguret

score 0 · Answer 5 · answered May 14 '13 at 09:43

0

window.location.href.substr(0, window.location.href.indexOf('#')) will do the trick

answered May 14 '13 at 09:43

Peter Schoep

5 Answers5