How to call a function with n parameters, with n set dynamically?

Question

Is there a way to pass the same parameter n times to a function?

For example:

if len(menu) == 1:
    gtk.ListStore(str)
elif len(menu) == 2:
    gtk.ListStore(str, str)
elif len(menu) == 3:
    gtk.ListStore(str, str, str)

Something like this, but "automatic"...

possible duplicate of [\*args and \*\*kwargs?](http://stackoverflow.com/questions/3394835/args-and-kwargs) — Ben, May 16 '13 at 12:23

score 2 · Answer 1 · answered May 16 '13 at 12:27

2

I'm sure what you mean is:

gtk.ListStore(*menu)

Sequences can be splatted into the positional arguments of a function call. The splat must go at the end of positional arguments, ie:

foo(1, 2, *bar)

is OK, but you can't do

foo(1, *bar, 2)

answered May 16 '13 at 12:27

SingleNegationElimination

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score 1 · Answer 2 · answered May 16 '13 at 12:25

1

def  ListStore(*str_collection): #collect arguments passed into str_collection which is a tuple
    for s in str_collection:
        print(s)

ListStore("A","B","C")

Outputs:

>>> 
A
B
C

str_collection has type:

>>> 
<type 'tuple'>

answered May 16 '13 at 12:25

HennyH

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score 0 · Accepted Answer · answered May 16 '13 at 12:27

0

Use the following syntax:

gtk.ListStore(*[str] * len(menu))

answered May 16 '13 at 12:27

Yossi

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although this is a faitful translation of what stefa has provided in his question, I suspect `str` is meant to be a metasyntactic variable, short hand to emphasize the *number* of arguments, not their content. – SingleNegationElimination May 16 '13 at 12:28
No, this is exactly what I wanted to do. Thanks. – stevereds May 16 '13 at 12:42

How to call a function with n parameters, with n set dynamically?

3 Answers3