Comma Separated Numbers Regex

Question

I am trying to validate a comma separated list for numbers 1-8.

i.e. 2,4,6,8,1 is valid input.

I tried [0-8,]* but it seems to accept 1234 as valid. It is not requiring a comma and it is letting me type in a number larger than 8. I am not sure why.

The comma needs to be outside the character class, and grouped to the numeric character using parentheses. That is: `([0-8],)+` — Asad Saeeduddin, May 18 '13 at 05:22
You say you want the number 1-8, but your regex is trying to match 0-8. Which is it? — Cairnarvon, May 18 '13 at 05:27
Just for the answer to your question be somewhat explicit here; if it accepts 1234 as valid it will accept abcd as well, as there are 0 matches which is what you asked for with * — jdavid_1385, Feb 02 '17 at 12:27

Cairnarvon · Accepted Answer · 2013-05-18T05:34:05.123

69

[0-8,]* will match zero or more consecutive instances of 0 through 8 or ,, anywhere in your string. You want something more like this:

^[1-8](,[1-8])*$

^ matches the start of the string, and $ matches the end, ensuring that you're examining the entire string. It will match a single digit, plus zero or more instances of a comma followed by a digit after it.

edited May 18 '13 at 05:34

answered May 18 '13 at 05:24

Cairnarvon

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it will break if I will try to check against the values 1234, 1345 , 4455 – Ankit Vishwakarma Mar 10 '18 at 05:22
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In a more general case, [`^[0-9]+(,[0-9]+)*$`](https://regex101.com/r/xbxBV7/1) (since the title - *Comma Separated Numbers Regex* - sounds broader than what OP describes in the question body). – Wiktor Stribiżew Jul 13 '18 at 10:15
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@WiktorStribiżew in an even more general case, you could use `^\d+(,\d+)*$` because `\d` means "digit", or `[0-9]` in base 10 – chharvey Nov 30 '18 at 16:46
@chharvey `\d` is not supported by some regex engines, like POSIX, so `[0-9]` is safer in the context of a question that has only one, `regex`, tag. This is why I did not use a non-capturing group in my answer. – Wiktor Stribiżew Nov 30 '18 at 17:21

score 32 · Answer 2 · edited Sep 13 '18 at 19:47

32

/^\d+(,\d+)*$/

for at least one digit, otherwise you will accept 1,,,,,4

edited Sep 13 '18 at 19:47

als

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answered Mar 10 '18 at 05:34

Ankit Vishwakarma

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OP is trying to validate a comma-separated list of digits from 0 through 8 inclusive, not a comma-separated list of any number of digits. – Paul Jul 09 '18 at 14:55
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But it actually answers the 'headline' question which is why I'm here – zzapper Mar 01 '19 at 15:41

Jimmy · Answer 3 · 2019-10-02T08:58:13.617

10

[0-9]+(,[0-9]+)+

This works better for me for comma separated numbers in general, like: 1,234,933

edited Oct 02 '19 at 08:58

answered Jan 21 '19 at 09:03

Jimmy

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score 1 · Answer 4 · answered May 18 '13 at 05:39

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You can try with this Regex:

^[1-8](,[1-8])+$

answered May 18 '13 at 05:39

Santosh Panda

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score 1 · Answer 5 · answered Mar 06 '20 at 10:12

If you are using python and looking to find out all possible matching strings like XX,XX,XXX or X,XX,XXX or 12,000, 1,20,000 using regex

string = "I spent 1,20,000 on new project "
re.findall(r'(\b[1-8]*(,[0-9]*[0-9])+\b)', string, re.IGNORECASE)

Result will be --->  [('1,20,000', ',000')]

quux00 · Answer 6 · 2013-05-18T05:49:26.817

0

You need a number + comma combination that can repeat:

 ^[1-8](,[1-8])*$

If you don't want remembering parentheses add ?: to the parens, like so:

 ^[1-8](?:,[1-8])*$

edited May 18 '13 at 05:49

answered May 18 '13 at 05:24

quux00

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21,22,24,343546 is valid with this expression. The highest number can only be 8 – Nick LaMarca May 18 '13 at 05:34

Comma Separated Numbers Regex

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