Why does a recursive constructor call make invalid C# code compile?

Question

After watching webinar Jon Skeet Inspects ReSharper, I've started to play a little with recursive constructor calls and found, that the following code is valid C# code (by valid I mean it compiles).

class Foo
{
    int a = null;
    int b = AppDomain.CurrentDomain;
    int c = "string to int";
    int d = NonExistingMethod();
    int e = Invalid<Method>Name<<Indeeed();

    Foo()       :this(0)  { }
    Foo(int v)  :this()   { }
}

As we all probably know, field initialization is moved into constructor by the compiler. So if you have a field like int a = 42;, you will have a = 42 in all constructors. But if you have constructor calling another constructor, you will have initialization code only in called one.

For example if you have constructor with parameters calling default constructor, you will have assignment a = 42 only in the default constructor.

To illustrate second case, next code:

class Foo
{
    int a = 42;

    Foo() :this(60)  { }
    Foo(int v)       { }
}

Compiles into:

internal class Foo
{
    private int a;

    private Foo()
    {
        this.ctor(60);
    }

    private Foo(int v)
    {
        this.a = 42;
        base.ctor();
    }
}

So the main issue, is that my code, given at the start of this question, is compiled into:

internal class Foo
{
    private int a;
    private int b;
    private int c;
    private int d;
    private int e;

    private Foo()
    {
        this.ctor(0);
    }

    private Foo(int v)
    {
        this.ctor();
    }
}

As you can see, the compiler can't decide where to put field initialization and, as result, doesn't put it anywhere. Also note, there are no base constructor calls. Of course, no objects can be created, and you will always end up with StackOverflowException if you will try to create an instance of Foo.

I have two questions:

Why does compiler allow recursive constructor calls at all?

Why we observe such behavior of the compiler for fields, initialized within such class?

---

Some notes: ReSharper warns you with Possible cyclic constructor calls. Moreover, in Java such constructor calls won't event compile, so the Java compiler is more restrictive in this scenario (Jon mentioned this information at the webinar).

This makes these questions more interesting, because with all respect to Java community, the C# compiler is at least more modern.

This was compiled using C# 4.0 and C# 5.0 compilers and decompiled using dotPeek.

Answer 1

Interesting find.

It appears that there are really only two kinds of instance constructors:

1. An instance constructor which chains another instance constructor of the same type, with the : this( ...) syntax.
2. An instance constructor which chains an instance constructor of the base class. This includes instance constructors where no chainig is specified, since : base() is the default.

(I disregarded the instance constructor of System.Object which is a special case. System.Object has no base class! But System.Object has no fields either.)

The instance field initializers that might be present in the class, need to be copied into the beginning of the body of all instance constructors of type 2. above, whereas no instance constructors of type 1. need the field assignment code.

So apparently there's no need for the C# compiler to do an analysis of the constructors of type 1. to see if there are cycles or not.

Now your example gives a situation where all instance constructors are of type 1.. In that situation the field initaializer code does not need to be put anywhere. So it is not analyzed very deeply, it seems.

It turns out that when all instance constructors are of type 1., you can even derive from a base class that has no accessible constructor. The base class must be non-sealed, though. For example if you write a class with only private instance constructors, people can still derive from your class if they make all instance constructors in the derived class be of type 1. above. However, an new object creation expression will never finish, of course. To create instances of the derived class, one would have to "cheat" and use stuff like the System.Runtime.Serialization.FormatterServices.GetUninitializedObject method.

Another example: The System.Globalization.TextInfo class has only an internal instance constructor. But you can still derive from this class in an assembly other than mscorlib.dll with this technique.

Finally, regarding the

Invalid<Method>Name<<Indeeed()

syntax. According to the C# rules, this is to be read as

(Invalid < Method) > (Name << Indeeed())

because the left-shift operator << has higher precedence than both the less-than operator < and the greater-than operator >. The latter two operarors have the same precedence, and are therefore evaluated by the left-associative rule. If the types were

MySpecialType Invalid;
int Method;
int Name;
int Indeed() { ... }

and if the MySpecialType introduced an (MySpecialType, int) overload of the operator <, then the expression

Invalid < Method > Name << Indeeed()

would be legal and meaningful.

---

In my opinion, it would be better if the compiler issued a warning in this scenario. For example, it could say unreachable code detected and point to the line and column number of the field initializer that is never translated into IL.

Answer 2

I think because the language specification only rules out directly invoking the same constructor that is being defined.

From 10.11.1:

All instance constructors (except those for class object) implicitly include an invocation of another instance constructor immediately before the constructor-body. The constructor to implicitly invoke is determined by the constructor-initializer

...

• An instance constructor initializer of the form this(argument-listopt) causes an instance constructor from the class itself to be invoked ... If an instance constructor declaration includes a constructor initializer that invokes the constructor itself, a compile-time error occurs

That last sentence seems to only preclude direct calling itself as producing a compile time error, e.g.

Foo() : this() {}

is illegal.

---

I admit though - I can't see a specific reason for allowing it. Of course, at the IL level such constructs are allowed because different instance constructors could be selected at runtime, I believe - so you could have recursion provided it terminates.

---

I think the other reason it doesn't flag or warn on this is because it has no need to detect this situation. Imagine chasing through hundreds of different constructors, just to see if a cycle does exist - when any attempted usage will quickly (as we know) blow up at runtime, for a fairly edge case.

When it's doing code generation for each constructor, all it considers is constructor-initializer, the field initializers, and the body of the constructor - it doesn't consider any other code:

• If constructor-initializer is an instance constructor for the class itself, it doesn't emit the field initializers - it emits the constructor-initializer call and then the body.

• If constructor-initializer is an instance constructor for the direct base class, it emits the field initializers, then the constructor-initializer call, and then then body.

In neither case does it need to go looking elsewhere - so it's not a case of it being "unable" to decide where to place the field initializers - it's just following some simple rules that only consider the current constructor.

Answer 3

Your example

class Foo
{
    int a = 42;

    Foo() :this(60)  { }
    Foo(int v)       { }
}

will work fine, in the sense that you can instantiate that Foo object without problems. However, the following would be more like the code that you're asking about

class Foo
{
    int a = 42;

    Foo() :this(60)     { }
    Foo(int v) : this() { }
}

Both that and your code will create a stackoverflow (!), because the recursion never bottoms out. So your code is ignored because it never gets to execute.

In other words, the compiler can't decide where to put the faulty code because it can tell that the recursion never bottoms out. I think this is because it has to put it where it will only be called once, but the recursive nature of the constructors makes that impossible.

Recursion in the sense of a constructor creating instances of itself within the body of the constructor makes sense to me, because e.g. that could be used to instantiate trees where each node points to other nodes. But recursion via the pre-constructors of the sort illustrated by this question can't ever bottom out, so it would make sense for me if that was disallowed.

Answer 4

I think this is allowed because you can (could) still catch the Exception and do something meaningfull with it.

The initialisation will never be run, and it will almost certaintly throw a StackOverflowException. But this can still be wanted behaviour, and didn't always mean the process should crash.

As explained here https://stackoverflow.com/a/1599236/869482