Why is my float automatically rounding and how do i get it to stop

Question

  float pageCount = 10/6;

should be 1.666 but it is giving 1.0

score 8 · Accepted Answer · answered May 22 '13 at 05:47

Your calculation is being done in integer type since both the operands are of int type

cast or mark atleast one of the operand as float.

float pageCount = 10/6f; //6f specifying 6 as float

or

float pageCount = ((float) 10)/6;

In your current form, both operands are of integer type and their division results in integer value that is why you get 1 not 1.666

score -1 · Answer 2 · answered May 22 '13 at 05:48

-1

Simple to the following 10.0/6

answered May 22 '13 at 05:48

Anirudh

This would result in an error `Cannot implicitly convert type 'double' to 'float'. An explicit conversion exists (are you missing a cast?)` – Habib May 22 '13 at 05:51
Using 0.0 results in a double. You really need to use f to declare a float. – Pierre-Luc Pineault May 22 '13 at 05:52

2 Answers2