class property inaccesible due to protection level

Question

here are my class declarations

public class PlacesAPIResponse
{
    public string formatted_address { get; set; }
    public Geometry geometry { get; set; }
    public Location location { get; set; }
    public string icon { get; set; }
    public Guid id { get; set; }
    public string name { get; set; }
    public string reference { get; set; }
    public string[] types { get; set; }
}
public class Geometry
{
    Location location { get; set; }
}
public class Location
{
    public double lat { get; set; }
    public double lon { get; set; }
}

when i try to access it like this, but i get an "inaccessible due to protection level"

PlacesAPIResponse response = new PlacesAPIResponse();
string lon = response.geometry.location.lon;

what could i be doing wrong ?

score 4 · Answer 1 · edited May 23 '17 at 12:05

4

You need to declare your Geometry.location field as public:

public class Geometry
{
    public Location location;
}

By default, when you do not explicitly declare the access modifier for a class member, the assumed accessibility for it is private.

From the C# Specification section 10.2.3 Access Modifiers:

When a class-member-declaration does not include any access modifiers, private is assumed.

As an aside, you may also consider making it a property (unless it's a mutable struct)

EDIT: In addition, even when you fix the access issue, Location.lon is declared as a double but you are implicitly assigning it to a string. You will need to convert it to a string as well:

string lon = response.geometry.location.lon.ToString();

edited May 23 '17 at 12:05

Community

1
1

answered May 23 '13 at 16:19

Chris Sinclair

22,858
3
52
93

i just tried it but it also added another error "The property or indexer 'Geometry.location' cannot be used in this context because the get accessor is inaccessible – Samuel Isola May 23 '13 at 16:31
@DimejiIsola Did you update it to be public? That is: `public Location location { get; set; }`? – Chris Sinclair May 23 '13 at 16:32

score 0 · Answer 2 · answered May 23 '13 at 16:20

0

The location property of Geometry doesn't specify an accessibility level. The default level is private.

answered May 23 '13 at 16:20

Servy

202,030
26
332
449

score 0 · Answer 3 · answered May 23 '13 at 16:20

0

Geometry.location has no access modifier so it is private by default

answered May 23 '13 at 16:20

Jason

15,915
3
48
72

score 0 · Accepted Answer · answered May 23 '13 at 16:21

0

Make location public. It is private by default.

public class Geometry
{
    public Location location;
}

And you can access lon as double

PlacesAPIResponse response = new PlacesAPIResponse();
double lon = response.geometry.location.lon;

answered May 23 '13 at 16:21

arunlalam

1,838
2
15
23

class property inaccesible due to protection level

4 Answers4