PHP renaming of input file issues

Question

I'm trying to rename the input file to be a .jpg after conversion, but for some reason I'm getting a file.png.jpg when I'm really looking for file.jpg

Here is my code:

$source = $path . $_POST['username']. "-" . $_FILES['t1']['name'];
$destination = $path . $_POST['username']. "-" . basename($_FILES['t1']['name']) . ".jpg";

and the $_FILES['t1']['name'] = file.png – Blynn May 28 '13 at 16:12 — Blynn, May 28 '13 at 16:12

score 2 · Accepted Answer · answered May 28 '13 at 16:16

2

Use pathinfo():

$source = $path . $_POST['username']. "-" . $_FILES['t1']['name'];
$path_parts = pathinfo( $_FILES['t1']['name'] );
$destination = $path . $_POST['username']. "-" . $path_parts['filename'] . ".jpg";

answered May 28 '13 at 16:16

Andrey Volk

3,513
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score 1 · Answer 2 · answered May 28 '13 at 16:17

Let's say that the variable $filename contains your image name with the png extension.

In order to change the extension to jpg , simply run it through this function :

function replace_extension($filename) {
    return preg_replace('/\..+$/', '.' . '.jpg', $filename);
}

score 0 · Answer 3 · answered May 28 '13 at 16:16

The basename() function includes the original files extension

Use the pathinfo() function to return an array of informatino about the file and use the filename with out the extension

Replace

$destination = $path . $_POST['username']. "-" . basename($_FILES['t1']['name']) . ".jpg";

with

$info = pathinfo($_FILES['t1']['name']);
$destination = $path . $_POST['username']. "-" . $info['filename'] . ".jpg";

score 0 · Answer 4 · answered May 28 '13 at 16:17

0

You can either use the second parameter to basename to kill the suffix

$filename = basename($_FILES['t1']['name'], ".png");

or you could do some string manipulation

$filename = substr($_FILES['t1']['name],0, strrpos($_FILES['t1']['name'], ".") -1);

answered May 28 '13 at 16:17

Orangepill

24,500
3
42
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score 0 · Answer 5 · edited May 23 '17 at 11:50

basename returns you the whole filename, including the file type suffix (i.e. ".jpg"). If you want to strip the suffix, you can call the function with a second parameter: basename($_FILES['t1']['name'], 'png').

But if you want to convert a png to a jpg, you can't just change the filename, you have to convert the file using special functions, see "Use PHP to convert PNG to JPG with compression?".

PHP renaming of input file issues

5 Answers5