JQuery - How i can compare two list

Question

i have one list and one DOM Object i need compare and get different value theirs

Example:

lista1 = ["type", "name","visible"] 
lista2 = Object {type: "button", name: "button", class: "buttonBlack", visible: "true", backgroundimage: "null"}

lista2 = Object.keys(list2);

i try:

for(var i = 0; i<lista1.length;i++)

    $.each(lista2,function(key,val){
        if(lista[i] == val){
         list2.remove(val);
        }      
    });
};

I want to get the items that are not equal between them

How can i make this ?

expected return:

["class","backgroundimage"]

Are you trying to find out if a key from array `list1` is missing from hash `list2`? — mgamba, May 31 '13 at 19:13
are lista1, lista2 lista, list2 completely different items or are they typos in your naming convention. — Patrick Evans, May 31 '13 at 19:15
It really isn't clear what you are trying to do. Please provide more information. — Felix Kling, May 31 '13 at 19:15
@Mgamba I want to get the items that are not equal between them — user2403131, May 31 '13 at 19:16
`i need compare and get different value theirs` What does this mean? — Narayana Nagireddi, May 31 '13 at 19:17
@user2403131: Yeah, that doesn't make sense. You are comparing two completely different things (an array and an object). How can they be "equal". Do you mean what mgamba said? — Matt Burland, May 31 '13 at 19:18
And please clarify your variable names. You have `list1`, `list2`, `lista1`, `lista2` and `lista`. Only `list1` and `list2` are defined. — Matt Burland, May 31 '13 at 19:20
but you are using several different variables and we dont know what they are, expand on what each variable actually contains. — Patrick Evans, May 31 '13 at 19:21
Your result is just keys in `lista2` that are not in the array `lista1`. Do you also want values from `lista1` that are not keys in `lista2`? — Barmar, May 31 '13 at 19:28

score 2 · Accepted Answer · answered May 31 '13 at 19:34

list1 = ["type", "name","visible"] 
list2 = {type: "button", name: "button", class: "buttonBlack", visible: "true", backgroundimage: "null"}
result = []

$.each(list2, function(k,v){
  if ($.inArray(k, list1) === -1) {
    result.push(k)
  }
})

result
>> ["class", "backgroundimage"]

score 1 · Answer 2 · edited May 23 '17 at 10:31

1

var list1 = ["type", "name", "class", "visible", "backgroundimage", "disabled", "value"];
var list2 = {type: "button", name: "button", class: "buttonBlack", visible: "true", backgroundimage: "null"};

list2 = Object.keys(list2);

function arr_diff(a1, a2)
{
  var a=[], diff=[];
  for(var i=0;i<a1.length;i++)
    a[a1[i]]=true;
  for(var i=0;i<a2.length;i++)
    if(a[a2[i]]) delete a[a2[i]];
    else a[a2[i]]=true;
  for(var k in a)
    diff.push(k);
  return diff;
}

console.log(arr_diff(list1, list2));

results in

["disabled", "value"]

** based on
Get array of object's keys
JavaScript array difference

DEMO

edited May 23 '17 at 10:31

Community

1
1

answered May 31 '13 at 19:24

kei

20,157
2
35
62

`a` is being treated as an object but is defined as an array. – James Montagne May 31 '13 at 19:28
I need the left over from list2 list of key – user2403131 May 31 '13 at 19:31

score 0 · Answer 3 · answered May 31 '13 at 19:32

lista1 = ["type", "name","visible"] 
lista2 = Object {type: "button", name: "button", class: "buttonBlack", visible: "true", backgroundimage: "null"}

result = [];

for (var prop in lista2) {
   if (lista2.hasOwnProperty(prop) && lista1.indexOf(prop) < 0) {
       result.push(prop);
   }
}

The array result will contain all the properties of the object that aren't in your array.

JQuery - How i can compare two list

3 Answers3