NumberFormatException when parsing a Double from string

Question

Long story short here is my code that throws the number format exception:-

String percenta = "6.415‏";
holder.setPercent(Double.parseDouble(percenta));

I've tried a also Double.valueOf() but none of them work, still throws the same exception

here is the exception message

java.lang.NumberFormatException: For input string: "6.415‏"

what seems to be the problem here ?

EDIT

so the problem is in my encoding after all, how do i change that, I am using JSOUP to parse a page and it is supposed to be UTF-8, is Double.parseDouble not UTF-8 friendly ?

`` Shouldn't it be *«Double story short»*? `` – afsantos Jun 04 '13 at 10:37 — afsantos, Jun 04 '13 at 10:37

score 4 · Accepted Answer · answered Jun 04 '13 at 10:24

Try using:

NumberFormat format = NumberFormat.getInstance(Locale.US);
Number number = format.parse("6.415");
double d = number.doubleValue();

This may happen because of your internal Locale specification.

In order to verify it, check if it works:

String percenta = "6,415‏";
holder.setPercent(Double.parseDouble(percenta));

score 2 · Answer 2 · edited May 23 '17 at 11:43

2

I'd guess it is because your computer is running a non-English locale. Try Double.valueOf("6.415") for the English locale, or see Best way to parseDouble with comma as decimal separator? for more info on parsing.

edited May 23 '17 at 11:43

Community

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answered Jun 04 '13 at 10:25

Tom Carchrae

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score 2 · Answer 3 · answered Jun 04 '13 at 10:28

2

The choice of variable name percenta suggests that you're using the locale sk-SK.

The decimal separator for the locale is , and not ..

answered Jun 04 '13 at 10:28

devnull

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Ajinkya · Answer 4 · 2013-06-04T10:47:44.300

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6.415 is a valid value and should not throw a NumberFormatException.
Check your encoding. When I copy-pasted your code, got error while saving it.

enter image description here

edited Jun 04 '13 at 10:47

answered Jun 04 '13 at 10:23

Ajinkya

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how to check my encoding ? and how can I change the encoding of my characters ? – engma Jun 04 '13 at 10:37

score 0 · Answer 5 · answered Jun 04 '13 at 10:32

0

The encoding for the 'percenta = "6.415‏"' is not supported for Double to parse.

Please check the below error when I tried to copy your code.

enter image description here

answered Jun 04 '13 at 10:32

Munesh

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Why `6.415` is not supported? – Ajinkya Jun 04 '13 at 10:44

score 0 · Answer 6 · answered Jun 04 '13 at 10:34

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The problem is with the 6.415. It seems you are using keyboard that is not having compliant character encoding.

answered Jun 04 '13 at 10:34

Harish Kumar

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NumberFormatException when parsing a Double from string

6 Answers6