Math.random() should not repeat same number

Question

Here is the simple jquery to rotate array of strings

$.fn.loadText = function( textArray, interval ) {
    return this.each( function() {
        var obj = $(this);
        obj.fadeOut( 'slow', function() {
            obj.empty().html( random_array( textArray ) );
            obj.fadeIn( 'slow' );
        });
        timeOut = setTimeout( function(){ obj.loadText( textArray, interval )}, interval );
            if( !obj.is(':animated') ) { clearTimeout( timeOut ); obj.loadText( textArray, interval );} 
    });
}

function random_array( aArray ) {
    var rand = Math.floor( Math.random() * aArray.length + aArray.length );
    var randArray = aArray[ rand - aArray.length ];
    return randArray;
}

$(document).ready( function() {
    var textArray = ["murali","prashanth","nutal","candy"];
    $('#mydiv').loadText( textArray, 5000 );
});

Here is the problem, Newly generated random number should not be the same one as previously generated it should be new number so that the array of strings should not repeat again.Let's say if murali is generated then again murali should not generate may be other string should be displayed from array.Please help

JSFIDDLE LINK HERE

http://stackoverflow.com/questions/6625551/jquery-math-random-number-without-repeating-a-previous-number?rq=1 — rahularyansharma, Jun 05 '13 at 05:58

score 0 · Answer 1 · answered Jun 05 '13 at 06:01

0

(Step 1) Delete an array item after randomly selected a item
(Step 2) Repeat Step 1, until array is empty.

answered Jun 05 '13 at 06:01

invisal

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Math.random() should not repeat same number

1 Answers1