setColor method of GradientDrawable drawing different color

Question

I have a shape in layer-list and my goal is to change color of the shape programmatically at runtime. I have String for HEX code and I used Color.parseColor() to parse it and I passed to setColor method. Whenever I run the application it shows different color then I expect.

Here is my code for XML file :

<layer-list xmlns:android="http://schemas.android.com/apk/res/android" >


<item 
    android:id="@+id/lvbg"
    android:top="1dp">
    <shape
        android:id="@+id/listview_background"
        android:shape="rectangle" >
        <size
            android:height="220dp"
            android:width="600dp" >
        </size>

        <solid android:color="@android:color/black"></solid>

        <corners android:radius="15dp" />
    </shape>
</item>
</layer-list>

And this is my code in CustomAdapter :

convertView = mInflater.inflate(R.layout.student_info_selection_fragment_icon, null);
holder = new ViewHolder();
holder.collegeBG=(LayerDrawable)convertView.getResources().getDrawable(R.drawable.rectangle);
holder.bg = (GradientDrawable)holder.collegeBG.findDrawableByLayerId(R.id.lvbg);
String color = "#FF" + rowItem.getCollegeColor();
holder.bg.setColor(Color.parseColor(color));

For example when I put #FF1D0A63 I get black or brown, totally different colors. Thanks

Color codes in HEX format such as `232323` , `1D0A63` , `000000` — Gokhan Arik, Jun 06 '13 at 15:09
When I print the `color` there is no problem I get expected HEX results. `#FF232323` `#FF1D0A63` `#FF000000` and more. I guess the problem is about reaching 'shape' element in layer list. I am not sure if I'm reaching to 'shape' correctly — Gokhan Arik, Jun 06 '13 at 15:14
Reading this (http://stackoverflow.com/questions/7925978/android-gradient-drawable-color-change) I'm not sure it's possible... It's an old post but there have been no updates. — Ken Wolf, Jun 06 '13 at 15:33

score 4 · Answer 1 · answered Jun 07 '13 at 14:41

I still don't know what the problem is but I realized that when I use layer-list in xml and assign it as background to a view, and try to change color of a shape in layer-list I am having this problem.

So I solved it separating my background shape from layer-list.

I put my background shape to another file :

<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
    android:id="@+id/listview_background"
    android:shape="rectangle" >

    <size
        android:height="220dp"
        android:width="600dp" >
    </size>
    <solid android:color="@android:color/black" > </solid>
    <corners android:radius="15dp" />

</shape>

And I assigned it as a background to a TextView.

The reason I used layer-list was to combine 2-3 shapes and make them gradient and give them rounded corners. Instead I used View and TextView and assigned shapes to them as background and it worked.

Here is my new CustomAdapter:

convertView = mInflater.inflate(R.layout.student_info_selection_fragment_icon, null);
holder = new ViewHolder();
holder.tvBackground = (TextView) convertView.findViewById(R.id.tvSelectionCollegeBackground);
GradientDrawable background = (GradientDrawable) holder.tvBackground.getBackground();


String color = "#FF" + rowItem.getCollegeColor();
background.setColor(Color.parseColor(color));
holder.tvBackground.setBackground(background);

score 2 · Answer 2 · answered Nov 21 '17 at 07:09

try this code...

GradientDrawable gd = new GradientDrawable();
gd.setShape(GradientDrawable.RECTANGLE);
gd.setStroke(3, Color.BLUE);
gd.setSize(w, h);
gd.setColors(new int[]{
   Color.RED,
   Color.GREEN,
   Color.YELLOW,
   Color.CYAN
});
gd.setGradientType(GradientDrawable.LINEAR_GRADIENT);

setColor method of GradientDrawable drawing different color

2 Answers2