How to remove trailing zeros from a string?

Question

I have a string salePrice which can have values like 29.90000,91.01000 and i want to get the output like 29.90,91.01 as in with the two digits after decimal points. i am using a string.

Is there anything you have done to try to solve this problem? We will be more willing to answer your question if you tell us what you have tried so far. (Helpful links for asking better questions: [ask], [FAQ]) — tckmn, Jun 07 '13 at 12:45
@Raedwald Not a dup; this question wants to keep the last two digits — tckmn, Jun 07 '13 at 12:53
read this before you continue http://stackoverflow.com/questions/3730019/why-not-use-double-or-float-to-represent-currency , and http://download.java.net/jdk7/archive/b123/docs/api/java/text/NumberFormat.html — user902383, Jun 07 '13 at 16:23

Grzegorz Żur · Answer 1 · 2013-06-07T13:02:47.917

15

One of possible solutions

new BigDecimal("29.90000").setScale(2).toString()

Or if you need to round

new BigDecimal("29.90100").setScale(2, RoundingMode.HALF_UP).toString()

Using BigDecimal because converting from String to double can lose precision!

Choose rounding mode that fits your case.

edited Jun 07 '13 at 13:02

answered Jun 07 '13 at 12:45

Grzegorz Żur

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+1. `BigDecimal` is often overlooked. – fge Jun 07 '13 at 12:48
1

Oh, by the way, that's "lose" :p But a `double` indeed has loose precision :p – fge Jun 07 '13 at 12:49
1

@fge, **Good answer** must be **correct and funny**! – Grzegorz Żur Jun 07 '13 at 12:55
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BTW it will fail for 29.90100 – Evgeniy Dorofeev Jun 07 '13 at 12:57

score 8 · Answer 2 · answered Jun 07 '13 at 12:45

8

Try this...

DecimalFormat df2 = new DecimalFormat( "#,###,###,###.##" );
double dd = 100.2397;
double dd2dec = new Double(df2.format(dd)).doubleValue();

answered Jun 07 '13 at 12:45

MG_Bautista

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+1, but shouldn't it be `#,###,###,###.##`? Because the number doesn't always end with `0.00` – tckmn Jun 07 '13 at 12:46
@Doorknob Jeje... Fixed... – MG_Bautista Jun 07 '13 at 12:47
as a matter of fact it should be "0.00" instead to have fixed 2 digits after decimal point – Evgeniy Dorofeev Jun 07 '13 at 13:13

score 6 · Answer 3 · answered Jun 07 '13 at 12:45

6

int lastIndex = salePrice.indexOf(".") + 2
salePrice = salePrice.substring(0, lastIndex);

answered Jun 07 '13 at 12:45

Marvin Emil Brach

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score 2 · Answer 4 · answered Jun 07 '13 at 12:47

2

you can use

String.format("%.2f", value);

answered Jun 07 '13 at 12:47

Suresh Atta

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@yannishristofakis Thanks for sharing.value is a common term when representing some value.And convering value to string is not a big deal.So lets wait for OP response,weather he is able to get it or not.Good day. – Suresh Atta Jun 07 '13 at 13:05

giannis christofakis · Answer 5 · 2013-09-07T17:06:41.417

1

You can use Apache Commons Mathematics Library

    NumberFormat nf = NumberFormat.getInstance();
    nf.setMinimumFractionDigits(2);
    nf.setMaximumFractionDigits(2);
    ComplexFormat cf = new ComplexFormat(nf);
    Complex complex = cf.parse("29.90000");

edited Sep 07 '13 at 17:06

answered Jun 07 '13 at 13:21

giannis christofakis

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score 0 · Answer 6 · answered Jun 07 '13 at 14:29

Here is an old-school way that matches your question (you always want 2 decimal places)

public class LearnTrim
{
    public static void main(final String[] arguments)
    {
        String value1 = "908.0100";
        String value2 = "876.1";
        String value3 = "101";
        String value4 = "75.75";
        String value5 = "31.";

        System.out.println(value1 + " => " + trimmy(value1));
        System.out.println(value2 + " => " + trimmy(value2));
        System.out.println(value3 + " => " + trimmy(value3));
        System.out.println(value4 + " => " + trimmy(value4));
        System.out.println(value5 + " => " + trimmy(value5));
    }

    private static String trimmy(final String value)
    {
        int decimalIndex;
        String returnValue;
        int valueLength = value.length(); // use StringUtils.length() for null safety.

        decimalIndex = value.indexOf('.');
        if (decimalIndex != -1)
        {
            if (decimalIndex < (valueLength - 3))
            {
                returnValue = value.substring(0, valueLength - 2);
            }
            else if (decimalIndex == (valueLength - 3))
            {
                returnValue = value;
            }
            else if (decimalIndex == (valueLength - 2))
            {
                returnValue = value + "0";
            }
            else // decimalIndex == valueLength - 1
            {
                returnValue = value + "00";
            }
        }
        else
        {
            returnValue = value + ".00";
        }

        return returnValue;
    }
}

How to remove trailing zeros from a string?

6 Answers6

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