setMinimumFractionDigits(..) detail. NumberFormat class

Question

Directly from this java api

setMinimumFractionDigits
public void setMinimumFractionDigits(int newValue)
Sets the minimum number of digits allowed in the fraction portion of a number. minimumFractionDigits must be <= maximumFractionDigits. If the new value for minimumFractionDigits exceeds the current value of maximumFractionDigits, then maximumIntegerDigits will also be set to the new value.

What is the concern of maximumIntegerDigits with mimimumFractionDigits as specified in the above statement? (Exactly the following bit: "then maximumIntegerDigits will also be set to the new value"

[you can see here, for example](http://stackoverflow.com/a/8582656/714968) — mKorbel, Jun 07 '13 at 13:44

greedybuddha · Accepted Answer · 2013-06-07T13:52:14.580

1

It just means that if you are setting the minimum to be a value larger than the maximum, that the maximum will be set to the minimum number. This way no constraint is broken. It would be strange to have a minimum larger than the maximum.

Example:

num.setMaximumFractionDigits(5);
num.setMinimumFractionDigits(8);
// the maximum is automatically set to 8

The line you specified is actually a javadoc typo, they meant maximiumFractionDigit, from OpenJDK

public void setMinimumFractionDigits(int newValue) {
    minimumFractionDigits = Math.max(0,newValue);
    if (maximumFractionDigits < minimumFractionDigits) {
        maximumFractionDigits = minimumFractionDigits;
    }
}

edited Jun 07 '13 at 13:52

answered Jun 07 '13 at 13:41

greedybuddha

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They are referring to maximumIntegerDigits at the end.. not to maximumFractionDigits. That is what is not logic. – Rollerball Jun 07 '13 at 13:47
@Rollerball: Check my edit, you have found a typo in the javadoc, the code itself sets maximumFractionDigit. – greedybuddha Jun 07 '13 at 13:59

setMinimumFractionDigits(..) detail. NumberFormat class

1 Answers1