Display a webpage if direct access, but an image if embed content

Question

What I want is that with a URL, my site has a URL structure like this, http://mywebsite.com/page/test.gif, the test.gif is a GET parameter, thanks to .htaccess, I undestand that I can display a regular website doing so. I also understand that I could display the image directly using a gif file PHP header. What I want is to know if there is a way to check if user is coming from direct access or if the link is embeded and then switch from one option to another.

Thanks

http://stackoverflow.com/questions/13262436/hotlink-protection — mpm, Jun 08 '13 at 00:55
What I want is that: If hotlink, it's a website, if not hotlink, it's a gif image — steps, Jun 08 '13 at 06:10

score 0 · Answer 1 · edited May 23 '17 at 11:57

0

debug_backtrace() || die ("Direct access not premitted");

Add some HTML inside the die() command to display a webpage. I will go out on a limb and assume you don't want an entire webpage, just a message that indicates you can't use your images if requested.

Source: Here

edited May 23 '17 at 11:57

Community

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answered Jun 08 '13 at 02:42

David

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Display a webpage if direct access, but an image if embed content

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