PHP echo syntax, to scale an image

Question

I have the following syntax:

echo "<img src=\"images2/" . $row['image']  . "\" alt=\"\" /><br />"; }

I would like to a give a specific height and width for the image, but I can't to do it.

Have you made any research? Have you tried to google? What search requests have you used? — zerkms, Jun 10 '13 at 20:42
possible duplicate of http://stackoverflow.com/questions/1347675/html-img-scaling — Dave Chen, Jun 10 '13 at 20:43
You have a number of syntactical errors (related to escaping quotes) that will need to be resolved before your markup can be correctly rendered. Several of the answers below demonstrate ways to fix these typos. — zeantsoi, Jun 10 '13 at 20:51

zeantsoi · Answer 1 · 2013-06-10T21:02:28.120

You can specify dimensions directly in your HTML <img> tag:

echo "<img src=\"images2/\" . $row['image']  . "\" alt=\"\" height=\"100\" width=\"100\" /><br />";

Note that your posted code has a closing curly brace (}) following your echo statement, which will cause a PHP error if there's no corresponding opening curly brace. You're also incorrectly escaping the double-quotes after images2/, which will result in invalid markup.

A better approach would be to enclose your entire markup in single quotes so that you don't have to escape the double quotes enclosed within:

echo '<img src="images2/' . $row['image'] . '" alt="" height="100" width="100" /><br />';

EDIT:

For modern day markup (depending on your requirements), it's considered vastly preferable to modify image dimensions in CSS, rather than in your <img> tag. You may want to consider implementing something akin to the following:

<style type="text/css">
    img {
        width: 100px;
        height: 100px;
    }

    img.large {
        width: 200px;
        height: 200px;
    }
</style>

<?php

    echo '<img src="images2/' . $row['image'] . '" alt="" /><br />'; // no class attribute, so will default to 100x100  
    echo '<img src="images2/' . $row['image'] . '" alt="" class="large" /><br />'; // class attribute is `large`, so will rescale to 200x200

score 0 · Answer 2 · answered Jun 10 '13 at 20:43

0

This should work

echo '<img src="images2"'.$row['image'].'\ alt="" width="" height="" /><br />'; }

answered Jun 10 '13 at 20:43

Ali

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What is it supposed to do? – zerkms Jun 10 '13 at 20:43

PHP echo syntax, to scale an image

2 Answers2