Python encoding: list to string having special characters and numbers in the list

Question

I need to join something like this:

["Círculo", 23]
["Triángulo, 25, 19, "dos"]

But solutions like:

', '.join(map(str, myList)) or ', '.join(str(x) for x in list_of_ints)

does not work for me, because special character 'í' makes it fail:

UnicodeEncodeError: 'ascii' codec can't encode character ... in position ...: ordinal not in range(128)

So what is the pythonic way to solve it? I do not want to check types... Thx!

Are you able to define the list elements as unicode? Like this [u'Círculo', 23] It will solve your problem using @Blubber's answer — Ander2, Jun 11 '13 at 09:20

score 2 · Accepted Answer · answered Jun 11 '13 at 11:48

2

Checking about encodings I found a solution that works for me:

 u', '.join([unicode(x.decode('utf-8')) if type(x) == type(str()) else unicode(x) for x in a])

The trick is to use decode('utf-8') for getting a valid 8-bit representation of the character.

Hope this will help.

answered Jun 11 '13 at 11:48

Ander2

Thx @Ander2, I did not want to use type check but it looks like is the only way to do it... thx a lot – Alberto Megía Jun 11 '13 at 12:12

Blubber · Answer 2 · 2013-06-12T09:52:10.393

0

If you can specify the strings in your list as unicode, like:

[u"Círculo", 23]
[u"Triángulo", 25, 19, u"dos"]

then this should work:

u', '.join(unicode(x) for x in list_of_ints)

Assuming you are running Python 2.

edited Jun 12 '13 at 09:52

answered Jun 11 '13 at 09:08

Blubber

This is working only if you assume @Ander2 comment. Update the response and I will mark it as accepted :) – Alberto Megía Jun 11 '13 at 11:01

score 0 · Answer 3 · answered Jun 11 '13 at 09:37

0

import encodings

a=encodings.utf_16.decode(a[0])
encodings.utf_16.encode(a[0])

Have you tried to do it with the encodings module? Maybe you'll get it to work with this. But doesnt seem to work with the utf_16 encoding...

answered Jun 11 '13 at 09:37

gspoosi

3 Answers3