XMLHTTP request passing JSON string as raw post data

Question

My JavasSript sends the request:

var jax = new XMLHttpRequest();
jax.open("POST", "http://localhost/some.php", true);
jax.setRequestHeader("Content-Type", "application/json");
jax.send(JSON.stringify(jsonObj));
jax.onreadystatechange = function() {
    if(jax.readyState === 4) { console.log(jax.responseText);  }
}

Right now all my php does is:

print_r($HTTP_RAW_POST_DATA);
print_r($_POST);

The output from the raw post data is the object string, but the post array is empty.

{"name" : "somename", "innerObj" : {} ... }
Array
(
)

I need to get it in the proper format for the $_POST variable, and jquery isn't an option.

Have you tried `file_get_contents('php://input')`? – Elias Van Ootegem Jun 14 '13 at 17:56 — Elias Van Ootegem, Jun 14 '13 at 17:56

score 6 · Accepted Answer · answered Jun 14 '13 at 18:01

Right, since user1091949 posted my comment as an answer, here's the same thing again, so OP can choose who's answer to approve (if it worked):

$json = json_decode(file_get_contents('php://input'));

At this point, $json will be an instance of the stdClass... If you prefer an associative array, just pass a second parameter to json_decode('{"json":"string"}', true);

BTW: Never, Ever use the forbidden error-suppressor of death: @. Errors are there to help you, not to annoy you...

I posted your comment as an answer? – user1091949 Jun 14 '13 at 18:03 — user1091949, Jun 14 '13 at 18:03

score 0 · Answer 2 · answered Jun 14 '13 at 17:57

0

You need to get the raw post data:

if ($_SERVER['REQUEST_METHOD'] != 'POST') {
  exit;
}

$postdata = @file_get_contents("php://input");
$json = json_decode($postdata, true);

$json will be an associative array containing your JSON data.

answered Jun 14 '13 at 17:57

user1091949

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XMLHTTP request passing JSON string as raw post data

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