get all the images from a folder in php

Question

I am using WordPress. I have an image folder like mytheme/images/myimages.

I want to retrieve all the images name from the folder myimages

Please advice me, how can I get images name.

Answer 1

try this

$directory = "mytheme/images/myimages";
$images = glob($directory . "/*.jpg");

foreach($images as $image)
{
  echo $image;
}

Answer 2

you can do it simply with PHP opendir function.

example:

$handle = opendir(dirname(realpath(__FILE__)).'/pictures/');
while($file = readdir($handle)){
  if($file !== '.' && $file !== '..'){
    echo '<img src="pictures/'.$file.'" border="0" />';
  }
}

Answer 3

When you want to get all image from folder then use glob() built in function which help to get all image . But when you get all then sometime need to check that all is valid so in this case this code help you. this code will also check that it is image

  $all_files = glob("mytheme/images/myimages/*.*");
  for ($i=0; $i<count($all_files); $i++)
    {
      $image_name = $all_files[$i];
      $supported_format = array('gif','jpg','jpeg','png');
      $ext = strtolower(pathinfo($image_name, PATHINFO_EXTENSION));
      if (in_array($ext, $supported_format))
          {
            echo '<img src="'.$image_name .'" alt="'.$image_name.'" />'."<br /><br />";
          } else {
              continue;
          }
    }

If you do not want to check image type then you can use this code also

 $all_files = glob("mytheme/images/myimages/*.*");
 for ($i=0; $i<count($all_files); $i++)
 {
  $image_name = $all_files[$i];
  echo '<img src="'.$image_name .'" alt="'.$image_name.'" />'."<br /><br />";
 }

for more information

PHP Manual

Answer 4

Here is my some code

$dir          = '/Images';
$ImagesA = Get_ImagesToFolder($dir);
print_r($ImagesA);

function Get_ImagesToFolder($dir){
    $ImagesArray = [];
    $file_display = [ 'jpg', 'jpeg', 'png', 'gif' ];

    if (file_exists($dir) == false) {
        return ["Directory \'', $dir, '\' not found!"];
    } 
    else {
        $dir_contents = scandir($dir);
        foreach ($dir_contents as $file) {
            $file_type = pathinfo($file, PATHINFO_EXTENSION);
            if (in_array($file_type, $file_display) == true) {
                $ImagesArray[] = $file;
            }
        }
        return $ImagesArray;
    }
}

Answer 5

This answer is specific for WordPress:

$base_dir = trailingslashit( get_stylesheet_directory() );
$base_url = trailingslashit( get_stylesheet_directory_uri() );

$media_dir = $base_dir . 'yourfolder/images/';
$media_url = $hase_url . 'yourfolder/images/';

$image_paths = glob( $media_dir . '*.jpg' );
$image_names = array();
$image_urls = array();

foreach ( $image_paths as $image ) {
    $image_names[] = str_replace( $media_dir, '', $image );
    $image_urls[] = str_replace( $media_dir, $media_url, $image );
}

// --- You now have:

// $image_paths ... list of absolute file paths 
// e.g. /path/to/wordpress/wp-content/uploads/yourfolder/images/sample.jpg

// $image_urls ... list of absolute file URLs 
// e.g. http://example.com/wp-content/uploads/yourfolder/images/sample.jpg

// $image_names ... list of filenames only
// e.g. sample.jpg

Here are some other settings that will give you images from other places than the child theme. Just replace the first 2 lines in above code with the version you need:

From Uploads directory:

// e.g. /path/to/wordpress/wp-content/uploads/yourfolder/images/sample.jpg
$upload_path = wp_upload_dir();
$base_dir = trailingslashit( $upload_path['basedir'] );
$base_url = trailingslashit( $upload_path['baseurl'] );

From Parent-Theme

// e.g. /path/to/wordpress/wp-content/themes/parent-theme/yourfolder/images/sample.jpg
$base_dir = trailingslashit( get_template_directory() );
$base_url = trailingslashit( get_template_directory_uri() );

From Child-Theme

// e.g. /path/to/wordpress/wp-content/themes/child-theme/yourfolder/images/sample.jpg
$base_dir = trailingslashit( get_stylesheet_directory() );
$base_url = trailingslashit( get_stylesheet_directory_uri() );

Answer 6

$dir = "mytheme/images/myimages";
$dh  = opendir($dir);
while (false !== ($filename = readdir($dh))) {
    $files[] = $filename;
}
$images=preg_grep ('/\.jpg$/i', $files);

Very fast because you only scan the needed directory.

Answer 7

//path to the directory to search/scan
        $directory = "";
         //echo "$directory"
        //get all files in a directory. If any specific extension needed just have to put the .extension
        //$local = glob($directory . "*"); 
        $local = glob("" . $directory . "{*.jpg,*.gif,*.png}", GLOB_BRACE);
        //print each file name
        echo "<ul>";

        foreach($local as $item)
        {
        echo '<li><a href="'.$item.'">'.$item.'</a></li>';
        }

        echo "</ul>";

Answer 8

Check if exist, put all files in array, preg grep all JPG files, echo new array For all images could try this:

$images=preg_grep('/\.(jpg|jpeg|png|gif)(?:[\?\#].*)?$/i', $files);


if ($handle = opendir('/path/to/folder')) {

    while (false !== ($entry = readdir($handle))) {
        $files[] = $entry;
    }
    $images=preg_grep('/\.jpg$/i', $files);

    foreach($images as $image)
    {
    echo $image;
    }
    closedir($handle);
}

Answer 9

    <?php
   $galleryDir = 'gallery/';
   foreach(glob("$galleryDir{*.jpg,*.gif,*.png,*.tif,*.jpeg}", GLOB_BRACE) as $photo)
   {echo "<a  href=\"$photo\">\n" ;echo "<img style=\"padding:7px\" class=\"uk-card uk-card-default uk-card-hover uk-card-body\" src=\"$photo\">"; echo "</a>";}?>

UIkit php folder gallery https://webshelf.eu/en/php-folder-gallery/

Answer 10

// Store your file destination to a variable
$fileDirectory = "folder1/folder2/../imagefolder/";
// glob function will create a array of all provided file type form the specified directory
$imagesFiles = glob($fileDirectory."*.{jpg,jpeg,png,gif,svg,bmp,webp}",GLOB_BRACE);
// Use your favorite loop to display
foreach($imagesFiles as $image) {
    echo '<img src="'.$image.'" /><br />';
}

Answer 11

get all the images from a folder in php without database


$url='https://demo.com/Images/sliderimages/';
       $dir = "Images/sliderimages/";
        $file_display = array(
            'jpg',
            'jpeg',
            'png',
            'gif'
        );
        
        $data=array();
        
        if (file_exists($dir) == false) {
            $rss[]=array('imagePathName' =>"Directory  '$dir'  not found!");
            $msg=array('error'=>1,'images'=>$rss);
             echo json_encode($msg);
        } else {
            $dir_contents = scandir($dir);
        
            foreach ($dir_contents as $file) {
                @$file_type = strtolower(end(explode('.', $file)));
                // $file_type1 = pathinfo($file);
                // $file_type= $file_type1['extension'];
                
                if ($file !== '.' && $file !== '..' && in_array($file_type, $file_display) == true) {
                   $data[]=array('imageName'=>$url.$file);
               
                   
                }
            }
            if(!empty($data)){
                $msg=array('error'=>0,'images'=>$data);
                echo json_encode($msg);
            }else{
                $rees[]=array('imagePathName' => 'No Image Found!');
                $msg=array('error'=>2,'images'=>$rees);
                echo json_encode($msg);
            }
        }

Answer 12

You can simply show your actual image directory(less secure). By just 2 line of code.

 $dir = base_url()."photos/";

echo"<a href=".$dir.">Photo Directory</a>";