How do I split this line (in JavaScript) on the colons, except if the colon is preceded by http or https?

Question

I want to split this line:

at myFunc http://mysite.com/test.php:13:24

into this:

at myFunc http://mysite.com/test.php
13
24

I've tried using regexes (see below) but they're wrong:

line.split( /[^http]:/ );
line.split( /[^http][:]/ );
line.split( /(?!http):/ );
line.split( /(?!http)[:]/ );

How would I do this?

Search for "_lookbehinds_" and "_lookaheads_" in regular expressions. This should show you the way. — Tadeck, Jun 16 '13 at 01:33
I appreciate the help but you'll notice I was using one above and it still didn't work, so I'm not understanding *lookaheads* properly (and JavaScript doesn't have lookbehind). — Don Rhummy, Jun 16 '13 at 01:34
@DonRhummy: Yes, but searching for it would reveal this: http://stackoverflow.com/a/641432/548696 — Tadeck, Jun 16 '13 at 01:39
@Tadeck How does that help me? I don't see how to apply that to my need to split on the colon except where preceeded by http. They're replacing characters to find matches, but I need all the characters, just split. Please help me understand. — Don Rhummy, Jun 16 '13 at 01:40

tom · Accepted Answer · 2013-06-16T01:58:34.777

3

JavaScript doesn't have lookbehinds :(

var reverse = function(s) { return s.split('').reverse().join(''); };
var parts = reverse(line).split( /:(?!ptth)/ ).map(reverse).reverse();

var parts = line.split( /:(?!\/\/)/ );

var parts = line.match( /(.*):(.*):(.*)/ ) ;
parts.shift();

edited Jun 16 '13 at 01:58

answered Jun 16 '13 at 01:57

tom

Your "Tweaked problem #1" is so perfect, so simple. I should have seen it. Thanks! – Don Rhummy Jun 16 '13 at 02:11

1 Answers1