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If I have a function like this:

function [ out ] = call(a)
out = s.a
end

How can I get it to access the structure s.hello with call('hello') or someting like this?

side question: Is it also possible to access a Variable "hello" with such a function?

Thanks in advance, you guys are awesome!

Lasse
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1 Answers1

3

I would use dynamic structure access like so:

s.(a)

Learn more at the Mathworks website!

Also, if we look at your example function, I notice you're not passing in the structure as an argument, maybe it's global, but here an example of this technique using your function as a framework:

function out = call(s,a)
  out = s.(a);
end

Then to use the function, I try:

>> s = struct('hello',42)

s = 

    hello: 42

>> call(s,'hello')

ans =

    42

Works great with no recursion limit! If you're still getting a recursive function, try adding more of your code to the question, we'll get to the bottom of this!

HTH

Community
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macduff
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  • I tried that already, but it gives me errors, one was like this: ??? Maximum recursion limit of 500 reached. Use set(0,'RecursionLimit',N) to change the limit. Be aware that exceeding your available stack space can crash MATLAB and/or your computer. I simply used the structure like a.hello a.ciao And called it with the above state function test = call('hello') – Lasse Jun 20 '13 at 13:43
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    @Lasse, see my updates here, hope this is helpful! – macduff Jun 20 '13 at 14:08
  • okay, seems it had problems with the structure-name, which i also have to feed the function, right? – Lasse Jul 12 '13 at 13:07