I googled and tried lot of variants for some hours but without any success. Please help me to find a solution.
Spring version: Spring 3.1
I have login page. Login page depends on URL parameter:
/login?code=client1
or
/login?code=client2
So client1 and client2 has different login pages.
security.xml:
<sec:form-login login-page="/login" default-target-url="/start" authentication-failure-url="/login"/>
So if user make wrong authentication I show him /login page... But point is I have to show login page with corresponding code parameter.
What should I do? Have tyou examples please?
Thanks a lot for advance.
UPDATE #1:
I created FailureHandler class:
public class GRSAuthenticationFailureHandler extends SimpleUrlAuthenticationFailureHandler implements AuthenticationFailureHandler {
@Override
public void onAuthenticationFailure(HttpServletRequest request, HttpServletResponse response, AuthenticationException exception) {
}
}
What should I write inside to get redirect to needed URL? Please if you can give me more details.
Thanks a lot!