I'm using AngularUI's routing and I'd like to do a ng-class="{active: current.state}"
but I'm unsure how to exactly detect the current state in a directive like this.

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5 Answers
Update:
This answer was for a much older release of Ui-Router. For the more recent releases (0.2.5+), please use the helper directive ui-sref-active
. Details here.
Original Answer:
Include the $state service in your controller. You can assign this service to a property on your scope.
An example:
$scope.$state = $state;
Then to get the current state in your templates:
$state.current.name
To check if a state is current active:
$state.includes('stateName');
This method returns true if the state is included, even if it's part of a nested state. If you were at a nested state, user.details
, and you checked for $state.includes('user')
, it'd return true.
In your class example, you'd do something like this:
ng-class="{active: $state.includes('stateName')}"

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3What about for states that have parameters? – Bradley Trager Dec 27 '13 at 04:19
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3https://github.com/angular-ui/ui-router/wiki/Quick-Reference#stateincludesstatename--params – Matt Way Jan 09 '14 at 00:06
Also you can use ui-sref-active directive:
<ul>
<li ui-sref-active="active" class="item">
<a href ui-sref="app.user({user: 'bilbobaggins'})">@bilbobaggins</a>
</li>
<!-- ... -->
</ul>
Or filters:
"stateName" | isState
& "stateName" | includedByState

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If you are using ui-router, try $state.is();
You can use it like so:
$state.is('stateName');
Per the documentation:
$state.is ... similar to $state.includes, but only checks for the full state name.

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Check out angular-ui, specifically, route checking: http://angular-ui.github.io/ui-utils/

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