Python: subprocess and running a bash script with multiple arguments

Question

How do I go about running a bash script using the subprocess module, to which I must give several arguments?

This is what I'm currently using:

subprocess.Popen(['/my/file/path/programname.sh', 'arg1 arg2 %s' % arg3], \
    shell = True)

The bash script seems not to be taking any of the parameters in. Any insights are greatly appreciated!

score 53 · Accepted Answer · answered Jun 21 '13 at 19:57

53

Pass arguments as a list, see the very first code example in the docs:

import subprocess

subprocess.check_call(['/my/file/path/programname.sh', 'arg1', 'arg2', arg3])

If arg3 is not a string; convert it to string before passing to check_call(): arg3 = str(arg3).

answered Jun 21 '13 at 19:57

jfs

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If all of my args are variables, do I not set them as strings? – user2510173 Jun 21 '13 at 20:05
@user2510173: I don't understand the question. Here's an example: `arg3 = 1`, to convert it, you could call `str(arg3)` that returns `'1'`. – jfs Jun 21 '13 at 20:23
10

Unfortunately, the example in the code does not answer the original question, since they chose a too-simple case of just a single argument. It is unclear whether multiple arguments should be passed as a single string, or as multiple ones, unless you read well down the page to the details behind POpen. Even then, it only says, "Providing a sequence of arguments is generally preferred" - not, "you must supply multiple arguments as a list" – Steve Broberg Nov 21 '14 at 17:30
@SteveBroberg: do you mean the example in the official Python documentation? You can report it as a documentation bug at https://bugs.python.org ([patches are welcome](https://docs.python.org/devguide/docquality.html) but a simple report that points out a possible issue could be also useful). – jfs Dec 01 '14 at 16:22

score 15 · Answer 2 · answered Jun 21 '13 at 19:48

subprocess.Popen(['/my/file/path/programname.sh arg1 arg2 %s' % arg3], shell = True).

If you use shell = True the script and its arguments have to be passed as a string. Any other elements in the args sequence will be treated as arguments to the shell.

You can find the complete docs at http://docs.python.org/2/library/subprocess.html#subprocess.Popen.

score 3 · Answer 3 · edited Aug 30 '18 at 04:20

3

One more example, which is not included in all the above ones,

subprocess.Popen(['/your/script.sh %s %s %s' %(argument1,argument2,argument3)], shell = True)

Please note that, when you type %(argument1,argument2,argument3), there should not be any space between % and (, eg % (argument1,argument2,argument3) is not valid.

edited Aug 30 '18 at 04:20

LRE

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answered Oct 11 '17 at 10:39

YoungSheldon

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score 2 · Answer 4 · answered Oct 23 '16 at 04:02

Hi I know that this is solution is quite late, but could help someone.

example:

import subprocess
pass_arg=[]
pass_arg[0]="/home/test.sh"
pass_arg[1]="arg1"
pass_arg[2]="arg2"

subprocess.check_call(pass_arg)

The above example provides arg1 and arg2 as parameters to the shell script test.sh

Essentially, subprocess expects an array. So you could populate an array and provide it as a parameter.

score 1 · Answer 5 · answered Jun 21 '13 at 19:33

1

You forgot to add args name.

subprocess.Popen(args=['./test.sh', 'arg1 arg2 %s' % arg3], shell=True)

answered Jun 21 '13 at 19:33

loentar

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so the file path needs to be in the args set as well? – user2510173 Jun 21 '13 at 19:51

score 0 · Answer 6 · answered May 20 '22 at 20:13

0

This is how it worked for me

import subprocess
subprocess.Popen(["path/to/file.sh", arg1, arg2, arg3])

answered May 20 '22 at 20:13

A Campos

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Python: subprocess and running a bash script with multiple arguments

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