How to delete to the last blank characters on the line

Question

I have:

  int x = 1;______

(underscores means spaces) and I would like to get:

  int x = 1;

My naive solution is $bld$ , is there a quickest way?

In Emacs I use M-\ (delete-horizontal-space)

See also [How can you automatically remove trailing whitespace in vim](http://stackoverflow.com/questions/356126/how-can-you-automatically-remove-trailing-whitespace-in-vim) — Chris Morgan, Jun 22 '13 at 00:35
@doubleDown It's a sequence of key presses. $ moves the cursor to the end of the line, b moves the cursor to the end of the previous word, l moves the cursor one character to the right and d$ deletes everything from the cursor to the end of the line. — David Brown, Jun 22 '13 at 17:37

perreal · Answer 1 · 2013-06-22T02:55:17.367

2

For the current line:

:s/\s\+$

For all lines:

:%s/\s\+$

The substitution text can be omitted if blank, so we don't need to write s/\s\+$//.

edited Jun 22 '13 at 02:55

answered Jun 21 '13 at 23:48

perreal

1

`\+` is more efficient than `*`; it will mean that only lines with trailing whitespace will get altered, rather than every line. – Chris Morgan Jun 21 '13 at 23:52
I'd put it much stronger. `*` is simply a bad idea. Try `u` after it: every line has been modified, rather than just the lines which have actually been altered. Makes it hard to see what changed. – Chris Morgan Jun 22 '13 at 00:12

score 1 · Accepted Answer · answered Jun 21 '13 at 23:49

1

I do this with a search and replace mapping:

map <leader>W :%s/\s\+$//<CR>:let @/=''<CR>

:%s/\s\+$// deletes all trailing white space and then :let @/='' clears the search register.

answered Jun 21 '13 at 23:49

David Brown

score 0 · Answer 3 · answered Jun 21 '13 at 23:50

0

:%s/\s\+$//

What it does is it searches for white spaces at the end of the line and replace them by nothing.

answered Jun 21 '13 at 23:50

john mich

3 Answers3