Remove decimal places to certain digits without rounding

Question

I've found dozen of answers, but non of them is what I'm looking for, I don't want to round up or down, I know that I can round numbers as follow:

>>> print('%.3f' % 15.555555)
15.556

>>> round(15.555555, 3)
15.666

But I need to get 15.555. Should I use regex?

Yesss, Thanks alot should I delete my post? – eneepo Jun 23 '13 at 20:03 — eneepo, Jun 23 '13 at 20:03

score 9 · Answer 1 · answered Jun 23 '13 at 20:03

9

Cheeky solution:

numstring = str(15.555555)
num = float(numstring[:numstring.find('.')+4])

answered Jun 23 '13 at 20:03

Imre Kerr

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Konrad Borowski · Accepted Answer · 2014-04-11T20:01:45.450

6

My solution involving int abuse. int rounds towards the nearest 0. I multiply it by 10**3 to affect rounding. After using int, I divide it by 10**3 to get actual results.

It's safer, as it does work with e notation.

int(15.55555 * 10**3) / 10.0**3

edited Apr 11 '14 at 20:01

answered Jun 23 '13 at 20:04

Konrad Borowski

11,584
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`int(15.55555 * 10**3) / 10.0**3` – dansalmo Jun 23 '13 at 20:40
@dansalmo: Thanks, it's indeed better, as it works with negative numbers. Why I forgot about `int`, I'm not sure. – Konrad Borowski Jun 24 '13 at 10:56

Remove decimal places to certain digits without rounding

2 Answers2