Given a day, I want to get all days(datetime instances) of the week in which day is present.
I have a solution, please correct me if there is something wrong of if more efficient method exists.
>>> import datetime
>>> today = datetime.datetime(2013, 06, 26)
>>> today
datetime.datetime(2013, 6, 26, 0, 0)
>>> day_of_week = today.isocalendar()[2] - 1
>>> day_of_week
2
>>> start_date = today - timedelta(days=day_of_week)
>>> start_date
datetime.datetime(2013, 6, 24, 0, 0) # Got monday
>>> dates = [start + timedelta(days=i) for i in range(7)]
>>> dates
[datetime.datetime(2013, 6, 24, 0, 0),
datetime.datetime(2013, 6, 25, 0, 0),
datetime.datetime(2013, 6, 26, 0, 0),
datetime.datetime(2013, 6, 27, 0, 0),
datetime.datetime(2013, 6, 28, 0, 0),
datetime.datetime(2013, 6, 29, 0, 0),
datetime.datetime(2013, 6, 30, 0, 0)]
I want monday to be start date and sunday the end date.