Regular Expression For At Least One Number

Question

How would you create a regular expression for a value that should contain at least one number? The user can enter any special character, letter etc., but should contain at least one number.

I tried with pattern="[\w+]{6,20}" and

(?=.*\d)(*[a-z])(*[A-Z]).{6,20}

Neither are working.

Please, clarify: Any number or one from a range? The position of the number(s) inside the string. Why you marked that answer as correct? — Poniros, Feb 14 '19 at 22:07

code_rum · Accepted Answer · 2013-06-27T12:40:54.087

61

Try using this pattern

.*[0-9].*

For 6 to 20 use this

^(?=.*\d).{6,20}$

edited Jun 27 '13 at 12:40

answered Jun 27 '13 at 12:16

code_rum

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Shouldn't it be like this? : .*[0-9]+.* He writes "At Least One Number". Although the whole question is disappointing ( check comment ). – Poniros Feb 14 '19 at 21:56
@Poniros the + is redundant. Any more digit can be matched with `.*` which is placed before and after the token [0-9]. – paul Jun 28 '19 at 09:24

score 0 · Answer 2 · answered Jun 27 '13 at 12:12

0

You can use this pattern:

/^(?=.{6,20}$)\D*\d/

answered Jun 27 '13 at 12:12

Casimir et Hippolyte

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score 0 · Answer 3 · answered Aug 07 '21 at 02:07

0

/?=\D*\d/

/? is to check whether it has \D*

\D* means the following characters have no digits

\d refers to must have ending digit

answered Aug 07 '21 at 02:07

Alfred Huang

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Regular Expression For At Least One Number

3 Answers3

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