Regex to find a string after the last colon

Question

Here is some sample input:

<210>   DW_AT_name        : (indirect string, offset: 0x55): double
 <ae>   DW_AT_name        : (indirect string, offset: 0x24): long int
 <b5>   DW_AT_name        : int

I want to extract the string that represents the actual type. So my output would be:

double
long int
int

Here is the regex I have so far (double escaped because it's in Java):

.*DW_AT_name.*:\\s*([^:&&\\S]*)\\s*

It works for the int, but it doesn't work for the other two. I think the best solution is to basically say 'get everything after the last colon' but I'm not sure how. Note that it must also include the DW_AT_NAME stuff.

tckmn · Accepted Answer · 2013-06-27T23:39:16.933

8

You need no regex for this:

String yourString = "<210>   DW_AT_name        : (indirect string, offset: 0x55): double";
String result;
if (yourString.contains("DW_AT_name")) {
    int lastIndex = yourString.lastIndexOf(":");
    result = yourString.substring(lastIndex + 1).trim();
} else {
    result = "ERROR"; // or handle this however you want
}
System.out.println(result);

Simply find the last : and take everything after that. Then trim it to remove leading and trailing whitespace.

I edited my question, it needs to also check for DW_AT_name. String split wont [sic] do that.

Just use contains, then. (edited answer)

edited Jun 27 '13 at 23:39

answered Jun 27 '13 at 23:05

tckmn

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I edited my question, it needs to also check for DW_AT_name. String split wont do that. – David says Reinstate Monica Jun 27 '13 at 23:05
1

Might be better to use `String.lastIndexOf` instead of splitting (since you only care about the last token, anyways) – DannyMo Jun 27 '13 at 23:13

Adam Siemion · Answer 2 · 2013-06-27T23:12:02.210

0

This regexp ^.*DW_AT_name.*:\s*(.+)$ does the job as just tested on regexplanet.

edited Jun 27 '13 at 23:12

answered Jun 27 '13 at 23:06

Adam Siemion

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score 0 · Answer 3 · answered Jun 27 '13 at 23:11

0

String type = str.replaceAll(".*:(?=[^:]+$)", "");

answered Jun 27 '13 at 23:11

Bohemian

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http://stackoverflow.com/questions/17354662/regex-to-find-string-after-last-colon/17354682#comment25183234_17354682 – tckmn Jun 27 '13 at 23:12

score 0 · Answer 4 · answered Jun 27 '13 at 23:20

Try the next:

public static void main(String[] args) {

    String text = 
    "<210>   DW_AT_name        : (indirect string, offset: 0x55): double\n" + 
    "<ae>   DW_AT_name        : (indirect string, offset: 0x24): long int\n" + 
    "<b5>   DW_AT_name        : int";

    Pattern pattern = Pattern.compile("^.*DW_AT_NAME.*:\\s*([^:]+)$", 
            Pattern.CASE_INSENSITIVE);

    Scanner sc = new Scanner(text);
    while(sc.hasNextLine()) {
        String line = sc.nextLine();
        Matcher matcher = pattern.matcher(line);
        if (matcher.matches()) {
            System.out.println(matcher.replaceAll("$1"));
        }
    }

}

Output:

double
long int
int

Regex to find a string after the last colon

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