Get the src part of a string

Question

First post ever here, and i really hope you can help.

I use a database where a large piece of html is stored, now i just need the src part of the image tag.

I already found a thread, but i just doesn't do the trick.

My code:

Original string:

<p><img alt=\"\" src=\"http://domain.nl/cms/ckeditor/filemanager/userfiles/background.png\" style=\"width: 80px; height: 160px;\" /></p>

How i start:

$image = strip_tags($row['information'], '<img>');
echo stripslashes($image);

This returns:

<img alt="" src="http://domain.nl/cms/ckeditor/filemanager/userfiles/background.png" style="width: 80px; height: 160px;" />

Next step: extract the src part:

preg_match('/< *img[^>]*src *= *["\']?([^"\']*)/i', $image, $matches);

echo $matches ;

This last echo returns:

Array

What is going wrong?

Thanks in advance for your anwser.

You can use `print_r()` to see the contents of an array for debugging. — Bad Wolf, Jun 30 '13 at 16:10
Do it very dirty - `explode`on `src="`, then explode second value of result on `"`. — moonwave99, Jun 30 '13 at 16:13
use `print_r($matches)` instead of `echo $matches` so you will see the structure of `$matches`, because it is an array... not a single variable — tyrhus, Jun 30 '13 at 16:17

score 1 · Accepted Answer · edited May 23 '17 at 12:21

1

Using regexp to solve this kind of problem is a bad idea and will likely lead in unmaintainable and unreliable code. Better us an HTML parser.

Using simplehtmldom you can easily extract the src from the img tag:

foreach($html->find('img') as $element) 
       echo $element->src . '<br/>';

edited May 23 '17 at 12:21

Community

answered Jun 30 '13 at 16:18

Ivanka Todorova

1 Answers1