Basic python programming

Question

I don't know what is wrong. I tells me I have a string formatting error where a = y % 19 and then it also tells me I have something wrong with the module when I am calling the main(). No clue on how to fix this because it seems I am calling the main() function correctly and the string seems fine.

def main():

    y = input("Enter year: ")
    print ("y = ", y)

    a = y % 19
    print ("a = ", a)

    b = y / 100
    print ("b = ", b)

    c = y % 100
    print ("c = ", c)

    d = b / 4
    print ("d = ", d)

    e = b % 4
    print ("e = ", e)

    g = (8 * b + 13) / 25
    print ("g = ", g)

    h = (19 * a + b - d - g + 15) / 30
    print ("h = ", h)

    j = c / 4
    print ("j = ", j)

    k = c % 4
    print ("k = ", k)

    m = (a + 11 * h) / 319
    print ("m = ", m)

    r = (2 * e + 2 * j - k - h + m + 32)  % 7
    print ("r = ", r)

    n = (h - m + r + 90) / 25
    print ("n = ", n)

    p = (h - m + r + n + 19) % 32
    print ("p = ", p)

    print ("In ", y, "Easter Sunday is on", p,)
    if (n == 3):
        print ("March")
    if (n == 4):
        print ("April")

main()

Python version? and also post the full traceback. – Ashwini Chaudhary Jun 30 '13 at 17:57 — Ashwini Chaudhary, Jun 30 '13 at 17:57

score 4 · Answer 1 · answered Jun 30 '13 at 17:56

4

It seems like you're using Python 3. If so, the first problem is that y is a string (like "2013"), not a number (like 2013). The % operation means something different for strings than it does for numbers; you'll have to convert y to an integer by saying y = int(input('....')).

Not sure what the problem with the module is; can you post the exact error message and the way that you're running the code? (Is it in IDLE, by calling python myscript.py, or what?)

answered Jun 30 '13 at 17:56

Danica

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6
90
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It says traceback(most recent call last): File "EasterSunday.py". line 69 in main and then File "EasterSunday.py", line 24, in main a = y % 19. TypeError: not all arguments converted during string formatting – Suliman Sharif Jun 30 '13 at 18:00
Ah, that's only the one error! It's just showing you where the problem was located. – Danica Jun 30 '13 at 18:09
Okay so I tried changing the int in the year to enter but unfortunately now everything comes out as a decimal which I didn't want I tried putting int(input for the formulas but that didn't work. So it just won't now print the rest of my code correctly. – Suliman Sharif Jun 30 '13 at 18:14
Use `b = y // 100` to have it round the result down rather than put it as a decimal. Alternatively, you could use `b = int(y / 100)` if you wanted. – Danica Jun 30 '13 at 19:17

score 1 · Answer 2 · edited May 23 '17 at 11:56

1

input() returns a string. You may like to convert it to an int as x = int(input(...))

You may like to use raw_input() also if you're using Python v2.x, which also returns string but does not evaluate any expression.

Check here for more details.

edited May 23 '17 at 11:56

Community

1
1

answered Jun 30 '13 at 18:01

Vivek Jain

3,811
6
30
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score 0 · Answer 3 · answered Jun 30 '13 at 18:03

~$ python3 Test.py
Enter year: 2013
y =  2013
Traceback (most recent call last):
  File "Test.py", line 51, in <module>
    main()
  File "Test.py", line 6, in main
    a = y % 19
TypeError: not all arguments converted during string formatting

~$ python2.7 Test.py
Enter year: 2013
('y = ', 2013)
('a = ', 18)
('b = ', 20)
('c = ', 13)
('d = ', 5)
('e = ', 0)
('g = ', 6)
('h = ', 12)
('j = ', 3)
('k = ', 1)
('m = ', 0)
('r = ', 4)
('n = ', 4)
('p = ', 7)
('In ', 2013, 'Easter Sunday is on', 7)
April

Basic python programming

3 Answers3