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How can i parse the following string 2000-05-12T12:00 to year, month, date, hourOfDay, minute, second?

I know to parse split it in "-" but there is efficient way to date for all the value?

I saw the solution like SimpleDateFormat parserSDF=new SimpleDateFormat("EEE MMM d HH:mm:ss zzz yyyy");

but I need to update it to java calendar and i dont know how to do that?

James Berners
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  • Have you tried anything? – Rohit Jain Jul 01 '13 at 16:51
  • yes SimpleDateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd"); SimpleDateFormat timeFormat = new SimpleDateFormat("HH:mm:ss"); – James Berners Jul 01 '13 at 16:52
  • @JamesBerners for future reference, you can [edit] your questions to include new information. Othere are less likely to see it in a comment (and you also aren't limited by comment formatting). – jerry Jul 01 '13 at 16:58
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    `Date date = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm", Locale.FRANCE).parse(s); Calendar cal = Calendar.getInstance(); cal.setTime(date);` – Joop Eggen Jul 01 '13 at 17:02

2 Answers2

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You would need to use SimpleDateFormat. Have a look at the java docs. Also you would have to look at the Calendar class. Java docs are here.

Try this - 

String str = "2000-05-12T12:00"; 
SimpleDateFormat parserSDF = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm");
Date d = parserSDF.parse(str);

Calendar cal = Calendar.getInstance();
cal.setTime(d);

System.out.println(cal.get(Calendar.DAY_OF_MONTH));
System.out.println(cal.get(Calendar.MONTH)); // month in the Calendar class begins from 0
System.out.println(cal.get(Calendar.YEAR));
System.out.println(cal.get(Calendar.HOUR_OF_DAY));
System.out.println(cal.get(Calendar.MINUTE));
System.out.println(cal.get(Calendar.SECOND));
JHS
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try use from public SimpleDateFormat(String pattern) function.

read this page and (http://docs.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html#parse(java.lang.String, java.text.ParsePosition) for do it!

Vahid Kharazi
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