Bash - How to split a string with multiple words

Question

I have a long string like following:

string='lala1lala2lala3'

The objective is to loop through each of the 'yourid' and echo the id 12345, 34567 and 39201 for further processing. How can this be achieve through bash shell?

bash might be a bad choice. If you can, go with a language which has XML support such as Perl, Python, or TCL. — Hai Vu, Jul 02 '13 at 02:39

score 3 · Answer 1 · answered Jul 02 '13 at 04:00

3

GNU grep:

grep -oP '(?<=/yourid/)\d+' <<< "$string"

12345
34567
39201

answered Jul 02 '13 at 04:00

glenn jackman

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score 2 · Answer 2 · answered Jul 02 '13 at 02:42

2

Use a real XML parser. For instance, if you have XMLStarlet installed...

while read -r id; do
  [[ $id ]] || continue
  printf '%s\n' "${id#/yourid/}"
done < <(xmlstarlet sel -m -t '//span[@id]' -v ./@id -n <<<"<root>${string}</root>")

answered Jul 02 '13 at 02:42

Charles Duffy

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+1 xmlstarlet may not be as likely to be installed, but it's convenient that you can use ad hoc xpath expressions on the command-line. AFAIK, xsltproc requires you to use a stylesheet file. – Bill Karwin Jul 02 '13 at 02:44

perreal · Answer 3 · 2013-07-02T04:07:55.657

1

With Perl:

declare -a ids
ids=( $(perl -lne 'while(m!yourid/(\w+)!g){print $1}' <<< "$string") )
echo ${ids[@]}

edited Jul 02 '13 at 04:07

answered Jul 02 '13 at 02:42

perreal

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Bash - How to split a string with multiple words

3 Answers3