The field is ambiguous while it is clearly hidden

Question

I know and fully agree that sharing constants through interfaces is considered as a bad practice, but I didn't choose this implementation. Whatever:

interface SuperClassConstants {
    public static final String CONSTANT = "super";
}

interface SubClassConstants extends SuperClassConstants {
    public static final String CONSTANT = "sub";
}

class SuperClass implements SuperClassConstants {
}

class SubClass extends SuperClass implements SubClassConstants {
    public SubClass() {
        System.out.println(CONSTANT);
        // The field CONSTANT is ambiguous
    }
}

Why ambiguous? Isn't the constant hidden? I thought Java would have understood I was expecting "sub"...

But your `SubClass` class can access to both interfaces... – Luiggi Mendoza Jul 02 '13 at 16:04 — Luiggi Mendoza, Jul 02 '13 at 16:04

AllTooSir · Accepted Answer · 2013-07-02T16:19:05.327

As per the JLS 9.3:

If two fields with the same name are inherited by an interface because, for example, two of its direct superinterfaces declare fields with that name, then a single ambiguous member results. Any use of this ambiguous member will result in a compile-time error.

The field CONSTANT in SubClassConstants has hidden the CONSTANT of SuperClassConstants. But the class SubClass has access to both the CONSTANT as it virtually implements both the interfaces.

You can remove the ambiguity by specifying the Interface name :

System.out.println(SubClassConstants.CONSTANT);

The field is ambiguous while it is clearly hidden

1 Answers1