How do I get all values of a foreach into a PHP variable?

Question

foreach ($tests as $test) {
  $var = $test['somekey'];
}
echo $var;

How do I get all values of a foreach into a php variable? It seems to be picking up only the last variable.

"Get into" how exactly? Put them into an array? `array_column`. — Jon, Jul 02 '13 at 22:35
Really unclear. Could be implode, or $test my be what you're after. Can you explain more? (Or just "echo" stuff out to see what's what) — Robbie, Mar 05 '14 at 12:51

score 2 · Accepted Answer · answered Jul 02 '13 at 22:35

2

you're overwriting $var on each iteration. with a dot as follows, this will append instead of overwrite.
$var .= $test['somekey'];

answered Jul 02 '13 at 22:35

Joe T

2,300
1
19
31

1

yes. that's it. thanks. I had forgotton – daily-learner Jul 02 '13 at 22:37
you should then mark the answer as correct – Saturnix Jul 02 '13 at 22:47
how do I do a conditional to check last item in array? – daily-learner Jul 02 '13 at 22:59
you could get the array size and compare to an iterative counter. `$count = count($tests); $i = 0; foreach ($tests as $test) { $i++; if ($i == $count) { # last element }` – Joe T Jul 02 '13 at 23:05

score 2 · Answer 2 · answered Jul 02 '13 at 22:51

The answer you're looking for depends on what you wish to do. If you wish for an array, use:

$var = array();
foreach ($tests as $test) {
    $var[] = $test['somekey'];
}
print_r($var);

or if you have PHP version >= 5.5.0 you can use:

$var = array_column($tests, $test);

If you wish for a string, use:

$var = "";
foreach ($tests as $test) {
    $var .= $test['somekey'];
}
print_r($var);

If you wish for a number, use:

$var = 0;
foreach ($tests as $test) {
    $var += $test['somekey'];
}
print_r($var);

You could also use any of the Assignment Operators instead of the += to do whatever you wanted!

A simple answer that saved my day. Thanks!! thats awesome that array [] brackets is what I needed — NJENGAH, Jul 28 '20 at 22:17

score 1 · Answer 3 · answered Jul 02 '13 at 22:35

1

How about:

$data = array() ;
foreach ($tests as $test) {
  $data[] = $test['somekey'];
}

echo implode(" ; ", $data) ;

answered Jul 02 '13 at 22:35

sybear

7,837
1
22
38

score 0 · Answer 4 · answered Jul 02 '13 at 22:39

0

You can try :

$var = array_map(function ($v) {
    return $v['somekey'];
}, $tests);

echo implode(PHP_EOL, $var);

answered Jul 02 '13 at 22:39

Baba

94,024
28
166
217

score 0 · Answer 5 · answered Jul 02 '13 at 22:46

it seems to be picking up the last variable only

That's because $var is a variable, not an array. You're just overriding the same variable multiple times: the only value which will remain is the last one.

Convert $var to an array in your code.

$var = new array();

then use something like array_push to add the value in the array

foreach ($tests as $test) {
  array_push($var, $test['somekey']);
}

finally, you may want to print out the value. echo is not the ideal way to print out an array. I'd recommend using print_r or var_dump enclosed in <pre> tags.

echo ("<pre>");
var_dump($var);
echo ("</pre>");

How do I get all values of a foreach into a PHP variable?

5 Answers5