number repeated twice in the variable

Question

#include <iostream>

using namespace std;

int main()
{
  int a = 101;
  return 0;
}

Question : How do I know that the number (1) is repeated twice in the variable

You use your eyeballs and determine it. If you want a more programmatic answer, you need to post a question that's more specific than this... such as posting what you've tried and how it was different from your expectations. — mah, Jul 05 '13 at 11:24
This may help you decide: [Is Anything Real?](http://www.youtube.com/watch?v=L45Q1_psDqk) — paddy, Jul 05 '13 at 11:24
Take a look at [What is the fastest way to check for duplicate digits of a number?](http://stackoverflow.com/questions/4801487/what-is-the-fastest-way-to-check-for-duplicate-digits-of-a-number) — Parag Bafna, Jul 05 '13 at 11:27
#include #include using namespace std; int main() { int a = 101; std::string s = std::to_string(a); size_t n = std::count(s.begin(), s.end(), '1'); //now you have number of "1" in n. Do whatever you want this. return 0; } — huseyin tugrul buyukisik, Jul 05 '13 at 11:31

score 8 · Accepted Answer · answered Jul 05 '13 at 11:23

8

If you look at the code, you will see that the number 101 is assigned to the variable a and that number has the digit 1 twice in its decimal representation. So direct inspection is the way to go. I wouldn't even write the code for such a trivial requirement.

answered Jul 05 '13 at 11:23

Luchian Grigore

253,575
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2

+1 This is **the** right answer. – Jul 05 '13 at 11:26
+1 This kind of reasoning should be taught at Computer Science 101. – Daniel Daranas Jul 05 '13 at 12:07

score 3 · Answer 2 · answered Jul 05 '13 at 11:25

3

Use modulus 10 and division 10 to find it. Rough idea is,

while( a > 0 )
{
    if( a % 10 == 1 )count_one++;
    a=a/10;
}

answered Jul 05 '13 at 11:25

VoidPointer

3,037
21
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thanks for all members – Anouar Benchekroun Jul 30 '13 at 22:18

number repeated twice in the variable

2 Answers2