How to get the position of the last match of a regex?

Question

I have a regex that matches numbers and I want to get the position of the last-matching number.

This is what I got right now:

def find_last_match_pos(pattern, s):
    match = None
    for match in re.finditer(pattern, s):
        pass
    return match.start() if match else -1

Can anyone think of a more pythonic way to do it?

Yeah I'm confident about the loop, I'm just wondering if there could be a clever trick involving `re`. — seriousdev, Jul 08 '13 at 20:46
@MartijnPieters, it appears it's not a duplicate because their is a solution specific to regular expressions. — Brigand, Jul 08 '13 at 22:32
I wouldn't say that that solution was more efficient, myself.. — Martijn Pieters, Jul 08 '13 at 22:39

mr2ert · Accepted Answer · 2013-07-08T20:57:59.583

3

Why not just use findall?

s.rfind(re.findall(pattern, s)[-1])

edited Jul 08 '13 at 20:57

answered Jul 08 '13 at 20:48

mr2ert

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Neat! Totally forgot about `str.rfind`. – seriousdev Jul 08 '13 at 21:31

How to get the position of the last match of a regex?

1 Answers1