Regex to allow any occurrence of one symbol in any position of the string?

Question

I'd appreciate if someone could help..

I need to allow the occurrence of dash (-) in any position of the string (except the beginning).

My RegEx is:

^[+]?[0-9]{3,10}$

I want to allow the following possibilities:

+7-777-77777
7-7-7-7-7-77

etc. so that I could have dash in any place after plus (+) and first digit.

Thank you in advance!

Can you tell us for what purpose? We might be able to suggest a better solution. — , Jul 09 '13 at 03:54

Anirudha · Accepted Answer · 2013-07-10T05:02:57.460

2

You can use lookahead

^(?=([^\d]*\d){3,10}[^\d]*$)[+]?\d+(-\d+)*$
 --------------------------
           |
           |->match further only if there are 3 to 10 digits in string

This would match string with three to 10 digits optionally having - in between the string

try it here

If you want optional space in between the strings

^(?=([^\d]*\d){3,10}[^\d]*$)[+]?\d+(\s*-\s*\d+)*$

edited Jul 10 '13 at 05:02

answered Jul 09 '13 at 03:46

Anirudha

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Thank you! Could you please also advise how to optionally have the space \s in between the same string? (along with - ) – Gyuzal Jul 10 '13 at 04:58
@GyuzalRakhmayeva a single space or more..also should the space occur anywhere in between the string – Anirudha Jul 10 '13 at 05:01

score 0 · Answer 2 · edited May 23 '17 at 12:29

0

I think the pattern you're looking for is this:

^[+]?[0-9][0-9-]{2,9}$

This will match an optional plus, followed by a decimal digit, followed 2 to 9 decimal digits or hyphens.

If you also want to ensure that the string doesn't end with a hyphen, simply use this:

^[+]?[0-9][0-9-]{1,8}[0-9]$

This will match an optional plus, followed by a decimal digit, followed 1 to 8 decimal digits or hyphens, followed by a decimal digit.

Note you can also extend this to all Unicode digits (see this answer for more information):

^\+?\d[\d-]{2,9}$

or

^\+?\d[\d-]{1,8}\d$

edited May 23 '17 at 12:29

Community

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answered Jul 09 '13 at 03:46

p.s.w.g

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i guess op wants to match 3 to 10 digits optionally having `-` anywhere – Anirudha Jul 09 '13 at 03:48

score 0 · Answer 3 · answered Jul 09 '13 at 03:51

0

http://rubular.com/r/8eyAolNHlX
In Ruby it should Works:

  /\+?(?:\d\-?\d?)+/

answered Jul 09 '13 at 03:51

Aguardientico

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score 0 · Answer 4 · answered Jul 09 '13 at 03:52

0

Maybe this?

^[+]?\d(-?\d){2,9}$

answered Jul 09 '13 at 03:52

Paul Chen

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score 0 · Answer 5 · answered Jul 09 '13 at 04:07

0

This requires the input start and end with a digit with optional plus at front

^\+?\d[\d-]{,8}\d$

answered Jul 09 '13 at 04:07

Bohemian

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Regex to allow any occurrence of one symbol in any position of the string?

5 Answers5