I know this answer was already answered and accepted, but I wanted to post a different approach I used, because this accepted answer wouldn't work if the button was over a background with another gradient, or an image, for example.
My solution works only for horizontal gradients and rounded-cornered (but not circle) buttons. I used both the "border-image" property and pseudo-elements to achieve this effect:
The button would have only the top and bottom "border-image" borders. The left and right borders would be completed with pseudo-elements.
Here's a working example:
HTML:
<div class="background">
<button class="button">
My button!
</button>
</div>
CSS:
*, *:before, *:after {
box-sizing: border-box;
}
.background {
background: linear-gradient(to bottom, #002e4b 0%,#1c4722 100%);
width:500px;
height:500px;
display:flex;
align-items:center;
justify-content:center;
}
.button {
box-sizing:border-box;
display: inline-block;
padding:0.5em 0;
background:none;
border:none;
border-top:2px solid #0498f8;
border-bottom:2px solid #0498f8;
border-image: linear-gradient(to right, #0498f8 0%, #4db848 100%);
border-image-slice: 1;
position: relative;
text-transform: lowercase;
transition:background 0.3s;
color: #fff;
cursor: pointer;
font-size:1em;
&:before,
&:after {
content: '';
display: block;
width: 2em;
height: calc(100% + 4px);
border-radius: 3em 0 0 3em;
border: 2px solid #0498f8;
position: absolute;
border-right: none;
transition:background 0.3s;
left: -2em;
top: -2px;
}
&:after {
border-radius: 0 3em 3em 0;
border: 2px solid #4db848;
position: absolute;
border-left: none;
left:auto;
right: -2em;
top: -2px;
}
&:hover {
background:rgba(0,0,0,0.3);
&:after,
&:before {
background:rgba(0,0,0,0.3);
}
}
}
https://jsfiddle.net/fnbq92sc/2/