What is the equivalent scala code to this python code: "%i" % float(9.04E09)

Question

I am a Scala noob. I am converting a python script to Scala. In one of my routine I am reading from a CSV file. The column is in scientific notation format. My code in python is:

"%i" % float(line[USER_ID]) where line[USER_ID] = "9.04E09"

This converts to "9040000000". How do I do this in Scala?

score 4 · Accepted Answer · answered Jul 09 '13 at 23:36

Using Scala 2.10 String interpolation:

scala> val numString = "9.04E09"
numString: String = 9.04E09

scala> val num = numString.toFloat
num: Float = 9.04E9

scala> val formatted = f"$num%1.0f"
formatted: String = 9040000000

If you are not using Scala 2.10, you'll have to do the String formatting yourself, which isn't really that different:

scala> val formatted = format("%1.0f", num)
formatted: String = 9040000000

I'm also assume your data is sanitized (i.e., no validation/exception is being done, in case your input string doesn't parse to a valid float).

I should mention that I assumed you want the output to remain a String, since that's what you have in your original Python version. If you want it to be an actual numeric type, Brian and Eran's answers are probably better. — Jack Leow, Jul 09 '13 at 23:43

score 1 · Answer 2 · edited May 23 '17 at 11:49

1

The Java way: (see here as well Java parse a number in exponential notation)

java.lang.Double.valueOf("9.04E09").longValue()

Another way in Scala:

"9.04E09".toDouble.longValue

Or

"9.04E09".toDouble.formatted("%.0f")

edited May 23 '17 at 11:49

Community

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answered Jul 09 '13 at 23:35

Eran Medan

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score 0 · Answer 3 · answered Jul 09 '13 at 23:41

0

You can use the Java API.

scala> val d = new java.lang.Double("9.04E09")
d: Double = 9.04E9

scala> val l = d.longValue
l: Long = 9040000000

answered Jul 09 '13 at 23:41

Brian

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What is the equivalent scala code to this python code: "%i" % float(9.04E09)

3 Answers3