Generate an incremental $variable when in a for loop

Question

i'd like to increment the variable within the for loop so that from "$filename" it turns into "$filename1" and then to $filename2"?

$filename = false;
$filename1 = false;
$filename2 = false;    

for ($i = null; $i <=2; $i++){
  $filename = $this->blabla;
}

Have you read about [arrays](http://php.net/array) yet? – mario Jul 11 '13 at 01:36 — mario, Jul 11 '13 at 01:36
yes i have, i'm just wondering if this could be done – Kyle McBride Jul 11 '13 at 01:37 — Kyle McBride, Jul 11 '13 at 01:37

score 2 · Accepted Answer · answered Jul 11 '13 at 01:38

2

Use variable variables:

${"filename".$i} = $this->blabla;

answered Jul 11 '13 at 01:38

Barmar

StackSlave · Answer 2 · 2013-07-11T02:00:14.283

0

Try, something like:

for($i=0; $i<3; $i++){
  $ii = $i === 0 ? '' : $i;
  ${"filename$ii"} = $this->blabla;
}

or

for($i=0; $i<3; $i++){
  $ii = $i === 0 ? '' : $i;
  $f = "filename$ii";
  $$f = $this->blabla;
}

edited Jul 11 '13 at 02:00

answered Jul 11 '13 at 01:41

StackSlave

PHP doesn't use `+` for concatenation. But even with that fix, it's not correct. – Barmar Jul 11 '13 at 01:43
I posted before I should have. – StackSlave Jul 11 '13 at 01:54

2 Answers2