How to convert an int pointer to the reference of an int array

Asked Jul 12 '13 at 08:46

Active Jul 12 '13 at 09:37

Viewed 136 times

I just come across the following problem:

void func( int (&arr)[3] ){...}

int main( int argc, char* argv[] )
{
    int* a = new int[3];
    a[0]=0, a[1]=1, a[2]=2;
    f(a);// how to convert a int* to int(&)[3]?

    delete[] a;

    return 0;
}

My point is how could I convert the pointer "a" to the required int array?

edited Jul 12 '13 at 09:37

asked Jul 12 '13 at 08:46

JavaBeta

This reeks of undefined behaviour. Why would you not just use a normal array? – chris Jul 12 '13 at 08:48
1

use delete [] a ( for new []) ..... – alexbuisson Jul 12 '13 at 08:50
1

`func( *reinterpret_cast(a) );` but I'm not sure if it's legal. – jrok Jul 12 '13 at 08:50
@jrok, You meant to put a reference, and I don't think it would be guaranteed to work, but it seems fairly reasonable it would. I'd rather not rely on it. – chris Jul 12 '13 at 08:52
No, the pointer is intended, notice I dereference it. – jrok Jul 12 '13 at 08:54
@jrok, Oh, I missed that tiny little star. – chris Jul 12 '13 at 08:56
This post here also has some good info https://stackoverflow.com/questions/20046429/casting-pointer-to-array-int-to-int2 – Evan Snapp Oct 02 '18 at 20:42

How to convert an int pointer to the reference of an int array

0 Answers0