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I have problem, I want to parse a log file, I want to print a line if the above line is containing a specific word,

for example

line 1 containing : aaa

line 2 containing : bbb

so, it will print out bbb

icodebuster
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rusa23
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    http://stackoverflow.com/questions/7451423/grep-a1-how-to-show-only-next-line-after-the-matched-one may have what you need –  Jul 15 '13 at 04:14

2 Answers2

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The -A n option to grep prints the next n lines after the matching line.

grep -A 1 aaa logfile
Barmar
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If you don't want the 'aaa' printed as well, you could use sed(1):

sed -n '/aaa/{n;p}'

Explanation: 

-n    don't print every line
/aaa/ when this pattern is matched, execute the block that follows
n     advance to the next line
p     print what's in the buffer
Aryeh Leib Taurog
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