Unless you add new client-side components to a Vaadin project, you don't need to compile a WidgetSet. However, the default configuration of Vaadin assumes that you have one. To get past this error simply remove the <init-param>
tag for the widgetset
in your web.xml
.
<servlet>
<servlet-name>Your-SERVLET-NAME</servlet-name>
<servlet-class>com.vaadin.server.VaadinServlet</servlet-class>
<init-param>
<param-name>UI</param-name>
<param-value>com.example.MyUI</param-value>
</init-param>
<init-param>
<param-name>widgetset</param-name>
<param-value>another.path</param-value>
</init-param>
</servlet>
Alternatively, you can create an .xml
file in the same package (e.g. MyWSet.xml
) as your UI class, and reference it in your web.xml
.
MyWSet.xml
in com.example
package:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE module PUBLIC "-//Google Inc.//DTD Google Web Toolkit 1.7.0//EN" "http://google-web-toolkit.googlecode.com/svn/tags/1.7.0/distro-source/core/src/gwt-module.dtd">
<module>
<inherits name="com.vaadin.DefaultWidgetSet" />
</module>
The right web.xml
:
<servlet>
<servlet-name>Your-SERVLET-NAME</servlet-name>
<servlet-class>com.vaadin.server.VaadinServlet</servlet-class>
<init-param>
<param-name>UI</param-name>
<param-value>com.example.MyUI</param-value>
</init-param>
<init-param>
<param-name>widgetset</param-name>
<param-value>com.example.MyWSet</param-value>
</init-param>
</servlet>
Remember, you don't need the .xml
suffix in your web.xml
. Finally, run mvn vaadin:compile
to compile this widgetset.