Convert JsonObject to String

Question

{
    "data": 
    {
        "map":
        {
            "allowNestedValues": true,
            "create": "2012-12-11 15:16:13",
            "title": "test201212110004",
            "transitions": []
        }
    },
    "msg": "success",
    "code": "0"
}

Above is a JsonObject, the data is a JsonObject.

How to convert it to a String like "msg":"success" as you know, i can't directly add a double quotes outside data's value.

I can't get it... Could you rephrase and give (even non-working) code snippets illustrating what you're attempting to do? — sp00m, Jul 15 '13 at 09:56
You can add doublequotes with a backslash `\"` if that´s what you want. Please add your problem/question! — Benjamin Schwalb, Jul 15 '13 at 09:58
Is that an instance of `org.json.JSONObject`? If it is, you can simply call `toString()` method of `JSONObject` to get JSON text of the`JSONObject`. — Stanley, Jul 15 '13 at 10:01
It looks like what people who land here 3+ years later are finding useful is not at all related to what was asked. And it also looks like the question is long past help at getting clarified. I believe the original question was that @JayZhang wanted to flatten the object, such that data was a string representation of its inner json value. It seems no one answered how to do that. Doing so years later would be unlikely to have any value to others. People are landing from searching for converting json to a string and getting mired in a confused Q&A session best deleted. — dlamblin, Sep 26 '17 at 04:19
It isn't just, as @dlamblin pointed out, that people are "landing" here years later, it's that the question really didn't have a lot to do with JSON in the first place. Yes, it does appear the OP wanted to know how to "flatten" the contents of "msg", but that gets into all sorts of questions about quoting quotes and "how does the OP expect to parse this thing and turn it back into something useful." There are some built-in string transforms, but with the OP's silence, who knows which one would have been most appropriate. — Julie in Austin, Sep 19 '18 at 19:01

score 212 · Answer 1 · edited Jul 17 '23 at 19:45

212

There is a built-in method to convert a JSONObject to a String. Why don't you use that:

JSONObject json = new JSONObject();

json.toString();

edited Jul 17 '23 at 19:45

Archmede

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answered Jul 15 '13 at 10:01

Tanu Garg

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{ "data": "{ "map": { "allowNestedValues": true, "pdId": 168543, "source": "" } }", "msg": "success", "code": "0" } – Jay Zhang Jul 15 '13 at 12:21
4

i'm getting \ \ \ slashes in response string. how to convert json object without getting \ \ \ slashes – Onkar Musale Apr 03 '19 at 04:53
@Onkar share your string sample along with code snippet. – Tanu Garg Apr 03 '19 at 05:25
similar to this thread. but unable to find answer. https://stackoverflow.com/q/16563579/8098322 – Onkar Musale Apr 03 '19 at 05:30
{"date":"2013/5/15"}. Are u using import org.json.JSONObject; its working fine for me. Share your exact sample. JSONObject json = new JSONObject(); try { json.put("date", "2013/5/15"); } catch (JSONException e) { // TODO Auto-generated catch block e.printStackTrace(); } System.out.println(json.toString()); – Tanu Garg Apr 03 '19 at 06:28
Is this the same for Java EE's JsonObject? – dko Apr 16 '21 at 02:41

score 25 · Answer 2 · edited Aug 24 '22 at 04:27

25

You can use:

JSONObject jsonObject = new JSONObject();
jsonObject.toString();

And if you want to get a specific value, you can use:

jsonObject.getString("msg");

or Integer value

jsonObject.getInt("codeNum");

For long Integers

jsonObject.getLong("longNum");

edited Aug 24 '22 at 04:27

sureshtechi

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answered Apr 18 '18 at 01:28

Janiel Mac

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It is better to use jsonObject.optString("msg") and jsonObject.optInt("codeNum") because if you use getString() or getInt() and the msg or codeNum values are null it'll throw and error and stop the program. Only difference with the methods I have mentioned is they won't throw an error if the values are null. – User1 Aug 26 '20 at 09:00

score 9 · Answer 3 · answered Jul 15 '13 at 10:01

9

you can use

JsonObject.getString("msg");

answered Jul 15 '13 at 10:01

Ruchira Gayan Ranaweera

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Naveen Kumar · Answer 4 · 2019-06-19T09:06:33.517

5

You can try Gson convertor, to get the exact conversion like json.stringify

val jsonString:String = jsonObject.toString()
val gson:Gson = GsonBuilder().setPrettyPrinting().create()
val json:JsonElement = gson.fromJson(jsonString,JsonElement.class)
val jsonInString:String= gson.toJson(json)
println(jsonInString)

edited Jun 19 '19 at 09:06

answered May 18 '19 at 12:57

Naveen Kumar

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score 4 · Answer 5 · answered May 20 '21 at 10:45

JsonObject seems to be JSON-P API. If this is true, I would use JsonWritter to write JsonValue into StringWriter:

    JsonObjectBuilder pokemonBuilder = Json.createObjectBuilder();
    pokemonBuilder.add("name", "Pikachu");
    pokemonBuilder.add("type", "electric");
    pokemonBuilder.add("cp", 827);
    pokemonBuilder.add("evolve", true);
    JsonObject pokemon = pokemonBuilder.build();
    StringWriter sw = new StringWriter(128);
    try (JsonWriter jw = Json.createWriter(sw)) {
        jw.write(pokemon);
    }
    String pokemonStr = sw.toString();

score 3 · Answer 6 · edited Feb 16 '16 at 14:25

3

Add a double quotes outside the brackets and replace double quotes inside the {} with \"

So: "{\"data\":{..... }"

edited Feb 16 '16 at 14:25

OverZealous

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answered Feb 16 '16 at 13:48

NargesooTv

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score 2 · Answer 7 · answered Feb 20 '22 at 08:52

2

Use This :

JSONObject json = new JSONObject();
JSONObject.valueToString(json.toString());

answered Feb 20 '22 at 08:52

Arman

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4

`JsonObject` =/= `JSONObject` – Elikill58 Feb 20 '22 at 10:29

score 1 · Answer 8 · answered Oct 26 '22 at 15:19

Example of Model

public class Person {
    private String name;
    private String age;
// setter and getter
// toString method
}

Example of Service method

public String getPerson() {
        JSONObject returnObj = new JSONObject();
        Person person = new Person();
        person.setAge("24");
        person.setName("Fazal");
        returnObj.put("age", person.getAge());
        returnObj.put("name", person.getName());
        return returnObj.toString();
    }

Json in java dependency needed

<!-- https://mvnrepository.com/artifact/org.json/json -->
<dependency>
    <groupId>org.json</groupId>
    <artifactId>json</artifactId>
    <version>{New_Version}</version>
</dependency>

You will get this type of JSON result

score 0 · Answer 9 · answered Apr 13 '17 at 10:57

0

JSONObject metadata = (JSONObject) data.get("map"); //for example
String jsonString = metadata.**toJSONString()**;

answered Apr 13 '17 at 10:57

Hakan Anlamaz

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JSONObject json= (JSONObject) JSONValue.parse(jsonData); JSONObject data = (JSONObject) json.get("data"); After you have parsed the json data, you need to access the data object later get "map" data to json string. – Hakan Anlamaz Apr 14 '17 at 13:50

vitalinvent · Answer 10 · 2021-12-08T11:52:36.410

0

just use ObjectMapper

ObjectMapper objectMapper = new ObjectMapper();
objectMapper.configure(SerializationFeature.FAIL_ON_EMPTY_BEANS,false);
//here more config opts...
Car car = new Car("yellow", "renault");
objectMapper.writeValue(new File("target/car.json"), car);
String carAsString = objectMapper.writeValueAsString(car);

edited Dec 08 '21 at 11:52

answered Dec 08 '21 at 11:46

vitalinvent

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Joel Wembo · Answer 11 · 2022-09-09T09:08:03.497

0

JSONObject data = (JSONObject) data.get("map"); 
 //for example
String jsonString = data.toJSONString();

edited Sep 09 '22 at 09:08

answered Sep 09 '22 at 08:55

Joel Wembo

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score -2 · Answer 12 · answered Dec 06 '16 at 15:02

     This should get all the values from the above JsonObject  
     System.out.println(jsonObj.get("msg"));
     System.out.println(jsonObj.get("code"));

     JsonObject obj= jsonObj.get("data").getAsJsonObject().get("map").getAsJsonObject();
     System.out.println(obj.get("allowNestedValues"));
     System.out.println(obj.get("create"));
     System.out.println(obj.get("title"));
     System.out.println(obj.get("transitions"));

this doesn't answer the question. – ralfe Feb 01 '18 at 14:03 — ralfe, Feb 01 '18 at 14:03

score -2 · Answer 13 · answered Dec 15 '17 at 12:33

You can use reliable library GSON

private static final Type DATA_TYPE_JSON = 
        new TypeToken<JSONObject>() {}.getType();           
JSONObject orderJSON = new JSONObject();
orderJSON.put("noOfLayers", "2");
orderJSON.put("baseMaterial", "mat");
System.out.println("JSON == "+orderJSON.toString());
String dataAsJson = new Gson().toJson(orderJSON, DATA_TYPE_JSON);
System.out.println("Value of dataAsJson == "+dataAsJson.toString());
String data = new Gson().toJson(dataAsJson);
System.out.println("Value of jsonString == "+data.toString());

score -5 · Answer 14 · edited Jun 30 '17 at 08:16

 var data= {"data": {"map":{"allowNestedValues": true,"create": "2012-12-11 15:16:13","title": "test201212110004","transitions": []}},"msg": "success","code": "0"}

o/p:

Object {data: Object, msg: "success", code: "0"}

Use JSON.stringify to convert entire data into string like below

var stringData = JSON.stringify(data);

o/p:

"{"data":{"map":{"allowNestedValues":true,"create":"2012-12-11 15:16:13","title":"test201212110004","transitions":[]}},"msg":"success","code":"0"}"

Use JSON.parse to convert entire string object into JSON Object like below

var orgdata = JSON.parse(stringData);

o/p:

Object {data: Object, msg: "success", code: "0"}

score -7 · Answer 15 · edited Dec 11 '15 at 07:42

I think you need this :

Suppose you have Sample JSON like this :

{"ParamOne":"InnerParamOne":"InnerParamOneValue","InnerParamTwo":"InnerParamTwoValue","InnerParamThree":"InnerParamThreeValue","InnerParamFour":"InnerParamFourValue","InnerParamFive":"InnerParamFiveValue"}}

Converted to String :

String response = {\"ParamOne\":{\"InnerParamOne\":\"InnerParamOneValue\",\"InnerParamTwo\":\"InnerParamTwoValue\",\"InnerParamThree\":\"InnerParamThreeValue\",\"InnerParamFour\":\"InnerParamFourValue\",\"InnerParamFive\":\"InnerParamFiveValue\"}} ;

Just replace " by \"

Convert JsonObject to String

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