How to get the application exit code from the Windows command shell?

Question

Of course, if possible, without any VBScript-like scripts.

score 4 · Accepted Answer · edited Jun 20 '20 at 09:12

4

Lastnico,

Hello, I think I have a solution to your problem. Try the following:

Try this at your command prompt:

C:\> cmd /c exit /b 4

C:\> echo %errorlevel%

The result should be 4.

Here is a screen shot of my result:

I hope this helps,

Thanks!

edited Jun 20 '20 at 09:12

Community

answered Nov 20 '09 at 18:16

Scott

Kaniabi · Answer 2 · 2009-11-25T11:37:13.310

1

The exit code is stored in the ERRORLEVEL environment variable:

echo %ERRORLEVEL%

To test it you can create a simple batch file that exits using the exit code passed as parameter:

exit_code.bat

@exit /b %1

Testing:

> exit_code.bat 8
> echo %ERRORLEVEL%
8

edited Nov 25 '09 at 11:37

answered Nov 20 '09 at 14:31

Kaniabi

1

my command line is always returning 9009 error code. Do you know why? – Lastnico Nov 20 '09 at 14:45
This doesn't seem to work for me. – Scott Nov 20 '09 at 18:11
It's just a typo in his code, it's supposed to be %1 instead of %i, no reason to downvote. – JRL Nov 20 '09 at 18:31
1

I can't un-downvote until the answer is edited. Kaniabi, if you edit your answer to correct, I should be able to un-downvote. Thanks! – Scott Nov 20 '09 at 18:42
Ops. Typo fixed. Thanks all for the feedback. – Kaniabi Nov 25 '09 at 11:37
Lastnico: Strange return code. I tried to execute with the typo and it always returns 0, not 9009. – Kaniabi Nov 25 '09 at 11:39