parse date with SimpleDateFormat

Question

I tried to parse this string 20130718T090000Z using SimpleDateFormat. I do like this:

        String timeString= "20130718T090000Z";
        DateFormat dateFormat = new SimpleDateFormat("yyyyMMdd'T'HHmmssZ");
        Date date= dateFormat.parse(timeString);

I received an Unparsable error. Referencing from here http://docs.oracle.com/javase/6/docs/api/java/text/SimpleDateFormat.html#rfc822timezone I found I did nothing wrong, or did I? Tks.

Tks all for quick and correct answers. I selected @sanbhat's one because he provides more info in his comment. — EyeQ Tech, Jul 19 '13 at 08:22

score 6 · Accepted Answer · answered Jul 19 '13 at 07:13

6

Use this format string "yyyyMMdd'T'HHmmss'Z'" . The reason why it did not parse was, the input had not parsable character Z at the end. "20130718T090000Z"

answered Jul 19 '13 at 07:13

sanbhat

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This will not help under all circumstances as if a time with another time zone appears it will fail. The letter `Z` is used to denote the time zone. – Uwe Plonus Jul 19 '13 at 07:15
@UwePlonus unfortunately java doesn't recognize ISO date format, so this is a way to ignore those charaters.http://stackoverflow.com/questions/2201925/converting-iso8601-compliant-string-to-java-util-date – sanbhat Jul 19 '13 at 07:16
I know this therefore you have to handle this manually in Java 6. Java 7 has a better support for this. – Uwe Plonus Jul 19 '13 at 07:18

Subir Kumar Sao · Answer 2 · 2013-07-19T08:25:44.130

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Z is for Time Zone. You did not provide the time zone in the date string.

You should have done some thing like String timeString= "20130718T090000-0700";

In case you wanted to treat Z as constant then you need to change the format to yyyyMMdd'T'HHmmss'Z'

edited Jul 19 '13 at 08:25

answered Jul 19 '13 at 07:16

Subir Kumar Sao

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score 0 · Answer 3 · answered Jul 19 '13 at 07:14

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You have the problem that the Z in your time String is not recognized as a valid time zone.

With Java 6 you have to handle the timezone Z on your own and either remove it or replace it with +0000.

answered Jul 19 '13 at 07:14

Uwe Plonus

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score 0 · Answer 4 · answered Jul 19 '13 at 08:27

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you have to give the value of Z in your input string . as String timeString= "20130718T090000+0000";

This will parse your date according to the format ..

Hope it helps

answered Jul 19 '13 at 08:27

Taranjit Kaur

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parse date with SimpleDateFormat

4 Answers4