double foo = 3;
double bar = 2.1;
System.out.println(foo - bar + "");
Output:
0.8999999999999999
Why? Is this some Java joke, which is not understandable for mere mortals?
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Lajos Arpad
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It isn't a joke. It is floating-point precision error problem. The main gist of this problem is that floating points are represented in base 2 rather than 10, and that the precision of doubles is not arbitrary.
If you want precision, you can use BigDecimal class:
jh314
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Thank you, this pretty much sums up things. – Lajos Arpad Jul 20 '13 at 02:48