Integer equals 0 instead of 1

Question

I don't understand why the values in the following code are not equal to 1:

var a:uint = (4.1-1.7)/2.4;
trace(a);//traces 0

var b:int = (4.1-1.7)/2.4;
trace(b);//traces 0

var c:Number = (4.1-1.7)/2.4;
trace(c);//traces 0.9999999999999998

[What every programmer should know about floating point](http://floating-point-gui.de/) — Barmar, Jul 20 '13 at 22:14
Sorry for the duplication. I did try to search before I posted the question. — Kasper Knudsen, Jul 20 '13 at 22:26
Adding to Chip's answer, because of the susceptible minor inaccuracies, each of your variables are equal to `0.9999999999999998`, but because the first two are typed as `uint` and `int`, those numbers are truncated (not rounded) down to `0`. — Chunky Chunk, Jul 21 '13 at 07:34

score 0 · Accepted Answer · answered Jul 20 '13 at 22:19

0

This is because in most languages real, non-integer numbers are stored using floating point representation (http://en.wikipedia.org/wiki/Floating_point), which is inherently susceptible to minor inaccuracies.

answered Jul 20 '13 at 22:19

Chip Camden

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Integer equals 0 instead of 1

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