Initializing a byte array from hex literals

Question

I have the following problem: I am sending an array to serial port it looks like this

 byte arr[] = new byte[]{0x18, 0x1B, 0x02, 0x05, 0xFF, 0x01, 0x10,
                         0x21,0x30, 0x00, 0x00, 0x6A, 0x28, 0x1B,0x03}

Here comes the problem - I have 3 text fields with R , G , B colors . I get the values from them as String.But I cant convert them to the above format 0xHexValue and put them in the byte array. I've tried a lot of approaches but without any success.

EDIT : I get the values from the text fields of the GUI with txtField.getText() after that there is no problem to convert in example R 200 , G 0 , B 0 to HEX C8 00 00 but I cant insert HEX into my byte array because it's still string . When i try to convert strings to byte with Byte.parseByte(s) some negative values appear....

EDIT 2 Byte.valueOf(myString) gets an exception on value 200

java.lang.NumberFormatException: Value out of range. Value:"200" Radix:10

GUYS: I see your posts and I suggest to focus on this : How to make in example this String "C8" to fit in the arr[] with the proper format 0xC8 and of course as byte not as String...

(Note that you'd need to somehow strip off the "0x" first, before using parseByte.) — Hot Licks, Jul 23 '13 at 12:11
Possibly see [this](http://stackoverflow.com/questions/8652804/how-to-convert-string-to-byte-in-java), [this](http://stackoverflow.com/questions/8652804/how-to-convert-string-to-byte-in-java). — AllTooSir, Jul 23 '13 at 12:12

Anirudha · Answer 1 · 2013-07-23T12:15:16.787

2

Use Byte.parseByte

Byte.parseByte(inputString,16);

16 is hexadecimal radix

You can also use Byte.decode

Byte.decode(inputString);//inputString can be decimal, hexadecimal, and octal numbers

edited Jul 23 '13 at 12:15

answered Jul 23 '13 at 12:10

Anirudha

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What do you assume the `input` to be in OP's case ? – AllTooSir Jul 23 '13 at 12:10
2

Please mention what sort of `String` i.e. contents of the string. – AllTooSir Jul 23 '13 at 12:11
@TheNewIdiot it could be anything "0x", "0X", "#", or leading zero – Anirudha Jul 23 '13 at 12:14
Not for me , please add it to the answer. – AllTooSir Jul 23 '13 at 12:15

score 1 · Answer 2 · answered Jul 23 '13 at 12:12

Try this:

    List<Byte> byteList = new ArrayList<>();
    String data = "0x18, 0x1B, 0x02, 0x05, 0xFF, 0x01, 0x10,0x21,0x30, 0x00, 0x00, 0x6A, 0x28, 0x1B,0x03";
    Pattern hexPattern = Pattern.compile("0x(..)");
    Matcher matcher = hexPattern.matcher(data);

    while(matcher.find()) {
        byteList.add((byte)Integer.parseInt(matcher.group(1), 16));
    }

    System.out.println(">>> " + byteList);

You can change the byteList by an actual byte array. Also, I'm assuming that you have your String in a certain way, but the idea is this one.

Initializing a byte array from hex literals

2 Answers2